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svp [43]
3 years ago
10

A rescue helicopter is used to help victims who fell in a ditch. The helicopter begins at sea level, which is an elevation of 0

feet. It then travels down for 100 seconds at a speed of 10.5 feet per second. It then travels directly up for 150 seconds at a speed of 5.2 feet per second. After this 250 second period, how much time, in seconds, will it take for the rescue helicopter to travel back to sea level at the helicopter's maximum speed of 15.8 feet per second?
Mathematics
1 answer:
Otrada [13]3 years ago
8 0

Answer:

The helicopter still needs to fly up sec 17.0886 at maximum speed.

Step-by-step explanation:


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Answer:

We have the sentence:

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Let's break it into parts.

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This can be written as:

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"...  2 by the power of -2 times x by the power of 0times x by the power of 9"

This can be written as:

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\frac{x^5*y^6}{2^{-2}*x^0*x^9}

And any number by the power of 0 is equal to 1, then:

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\frac{x^5*y^6}{2^{-2}*x^9}

We can keep simplifying this.

We know that:

a^(-n) = (1/a)^(n)

Then:

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Then we get:

\frac{x^5*y^6}{2^{-2}*x^9} = \frac{x^5*y^6}{x^9}*4

And we also know that:

a^n/a^m = a^(n - m)

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And we can't simplify this anymore.

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