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Amanda [17]
3 years ago
11

A student conducted a experiment on plant growth . Plant A was fed a different fertilizer than Plant B . Before the experiment b

egan,Plant A measured 14 centimeters tall, and Plant B measured 16 centimeters tall. At the end of the experiment,Plant A measured 18.2 centimeters tall, and Plant B measured 20 centimeters tall. Which plant, A or B, grew at a greater rate ?
Mathematics
1 answer:
Trava [24]3 years ago
3 0

Answer:Plant A


Step-by-step explanation: Plant A underwent 4.2 centimeters of growth, whereas Plant B underwent 4 centimeters of growth. Plant A grew more drastically than Plant B



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Please help me on this
Gre4nikov [31]

Answer: option a.

Step-by-step explanation:

Given the expression \sqrt{8^{17}}, you need to remember:

The Product of powers property:

a^m*a^n=a^{(m+n)}

The Power of a power property:

(a^m)^n=a^{mn}

And:

\sqrt[n]{a^n}=a

Therefore, as the index of the radical is 2, you can rewrite 8^{17} as:

8^{17}=8^{16}*8

Rewrite this and simplify. Then:

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=\sqrt{8^{16}*8}=\sqrt{8^{16}}\sqrt{8}=\sqrt{(8^{8})^2}\sqrt{8}=8^8\sqrt{8}

 

This matches with the option a.

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3 years ago
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iris [78.8K]

Answer:

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5 0
3 years ago
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konstantin123 [22]

Answer:

12mm

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Lorico [155]
128 - 16x

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