Answer: 
Step-by-step explanation:
Given
Box A has a volume of 
Box B is similar to box A such that box A dimension is multiplied by 4 to get the box B
So, each length is 4 times the box A and volume is the cube of the side.
Thus, the volume of box B is
the volume of box A
The volume of box B is

Answer: 1/3*2*2=2/6
Step-by-step explanation:
Hope this helps
I assume you're needing to find
given those two functions you have.
![\begin{aligned}(f+g)(x) &= f(x) + g(x) \\[0.5em] &= (5x^3+5x^2-6x+3) + (x^3-4x^2+x-2)\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%28f%2Bg%29%28x%29%20%26%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%5B0.5em%5D%20%26%3D%20%285x%5E3%2B5x%5E2-6x%2B3%29%20%2B%20%28x%5E3-4x%5E2%2Bx-2%29%5Cend%7Baligned%7D)
From there, you combine like terms:
![\begin{aligned}(f+g)(x) &= f(x) + g(x) \\[0.5em] &= (5x^3+5x^2-6x+3) + (x^3-4x^2+x-2) \\[0.5em] &= 6x^3+x^2-5x+1\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%28f%2Bg%29%28x%29%20%26%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%5B0.5em%5D%20%26%3D%20%285x%5E3%2B5x%5E2-6x%2B3%29%20%2B%20%28x%5E3-4x%5E2%2Bx-2%29%20%5C%5C%5B0.5em%5D%20%26%3D%206x%5E3%2Bx%5E2-5x%2B1%5Cend%7Baligned%7D)