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3 years ago

Count by ones from 392 to 500

Mathematics

2 answers:

MAVERICK [17]3 years ago

5 0

Count by ones from 392 to 500ok done
im not about to write all that out

Allisa [31]3 years ago

5 0

I am not going to write it all out. Its too much time wasted. Count yourself. Its as easy as a cake walk.

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One of the local homeless shelters received a donation of 852 blankets to help support the homeless population during the harsh

Arte-miy333 [17]

Answer:

Each shelter would get 121 blankets

And there would be 5 blankets left over

Step-by-step explanation:

One of the local homeless shelters received a donation of 852 blankets to help support the homeless population during the harsh winter months. They plan on distributing them to all 7 of the local shelters. How many blankets will each shelter get? Will there be any leftover? If so, how many?

From the above question

7 local shelters = 852 blankets

1 local shelters = x blankets

Cross Multiply.

7x = 852 blankets

x = 852 blankets/7

x = 121 5/7 blankets

Therefore, Each shelter would get 121 blankets

And there would be 5 blankets left over

7 0

2 years ago

Rachael is placing a protective cover on a glass case. The case is a cube, and the perimeter of one cube face is 56 inches.

Dmitry_Shevchenko [17]

Answer:

336

Step-by-step explanation:

We know that a cube has 6 faces which means we can use this equation:

56 x 6 = 336

336 square inches is the answer.

5 0

2 years ago

Read 2 more answers

Why were the two fractions able to settle their difference peacefully

professor190 [17]

They were both rational

3 0

3 years ago

Read 2 more answers

Complete the statements.

spayn [35]

Answer:

1. 30

2. 150

Step-by-step explanation:

$3tan^2(x)-1 =0$

Lets assume tan(x) = u

$3u^2(x)-1 =0$

Now we solve for 'u'

add 1 on both sides

$3u^2(x) =1$ , divide both sides by 3

$u^2 = \frac{1}{3}$

Take square root on both sides

$u = +-\frac{1}{\sqrt{3} }$

We replace tan(x) for 'u'

$tan(x) = +-\frac{1}{\sqrt{3} }$

x = 30 because $tan(30) =+\frac{1}{\sqrt{3} }$ in first quadrant

x = 30 (tan is positive in first quadrant)

$tan(x) =-\frac{1}{\sqrt{3} }$

x = 150 because $tan(150) =-\frac{1}{\sqrt{3} }$ in second quadrant

tan is negative in second quadrant

4 0

3 years ago

Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor

GarryVolchara [31]

Answer:

$\mu_p -\sigma_p = 0.74-0.0219=0.718$

$\mu_p +\sigma_p = 0.74+0.0219=0.762$

68% of the rates are expected to be betwen 0.718 and 0.762

$\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696$

$\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784$

95% of the rates are expected to be betwen 0.696 and 0.784

$\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674$

$\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806$

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

$p \sim N(p, \sqrt{\frac{p(1-p)}{n}})$

So then:

$\mu_p = 0.74$

$\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219$

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

$\mu_p -\sigma_p = 0.74-0.0219=0.718$

$\mu_p +\sigma_p = 0.74+0.0219=0.762$

68% of the rates are expected to be betwen 0.718 and 0.762

$\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696$

$\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784$

95% of the rates are expected to be betwen 0.696 and 0.784

$\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674$

$\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806$

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0

3 years ago