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2 years ago

Tell me which ones are greater than or lesser than with these <>?

Mathematics

1 answer:

Lesechka [4]2 years ago

8 0

Answer:

1. >

2.<

3.<

btw

Absolute value equations are equations where the variable is within an absolute value operator, like |x-5|=9. The challenge is that the absolute value of a number depends on the number's sign: if it's positive, it's equal to the number: |9|=9. If the number is negative, then the absolute value is its opposite: |-9|=9.

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Genrish500 [490]

Answer:

12 cm

Step-by-step explanation:

The Pythagorean Theorem is as follows:

$a^{2} +b^{2} =c^{2}$

A and B represent the side lengths (legs) and C represents the hypotenuse.

The length of one leg equals 5cm. (This can be represented by either a or b)

The hypotenuse equals 13 cm.

Plug these into the equation from above:

$a^{2} + (5^{2}) = (13^{2})$

Solve for the other leg:

$a^{2} + 25 = 169$ Square what's in the parentheses from above

$a^{2} = 144\\$ Subtract 25 from 169

$\sqrt{a^{2} } = \sqrt{144}$ Square root both sides

a = 12 cm

Thus, the length of the other leg is 12 cm.

Let's check our answer:

$12^{2} +5^{2} =13^{2}$ Square everything

144 + 25 = 169 Add

169 = 169

Because both sides are equal it means that 12 cm is the correct answer.

Hope this helps!!

3 0

2 years ago

Pls answer il make brainliest hurry

Liono4ka [1.6K]

Answer:

1/2

Step-by-step explanation:

6 0

3 years ago

MY TEACHER IS BEING ANNOYING HELP ME PLS

cluponka [151]

Answer:

Step-by-step explanation:

I got 8 in a short version. The full answer is not complete. It is 8.18812697...

But if you shorten it, 8 is the best estimation.

7 0

2 years ago

Prove that 1/sec0-tan0= sec0+tan0

Leviafan [203]

Answer:

Step-by-step explanation:

$\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}$

7 0

2 years ago

Write your answer without using negative exponents (u^4)^-7

umka21 [38]

Answer:

solution,

${(u}^{4} \: )^{ - 7} \\ = {(u)}^{4 \times ( - 7)} \\ = {(u)}^{ - 28} \\ = \frac{1}{ {u}^{28} }$

Hope this helps...

Good luck on your assignment..

7 0

3 years ago