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3 years ago

What fraction of a day is 15 hours

1 answer:

5 0

15/24 = 5/8

15 hours out of 24 hours.!!!!

5/8 of a day, or 0.625 as a decimal.

in minutes, it's 900/1,440

Hope this helps!!!!!

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In the diagram below, xy and z are tangent to 0. What is the measure of XZ?

VladimirAG [237]

Answer:

360 - 230 = 130°

Step-by-step explanation:

3 0

2 years ago

Solve for y.<br> 3X+2y=12

Montano1993 [528]

3x + 2y = 12

2y = -3x + 12
y = -1.5x + 6

3 0

3 years ago

Points P, Q, and S are collinear. What is m∠PQR? Straight angle P Q S is divided into 2 angles, P Q R and R Q S, by ray Q R. Ang

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

If P, Q and S are collinear, then the three points lies on the same straight line.

If the Straight <P Q S is divided into 2 angles, <P Q R and <R Q S, by ray Q R, then;

<P Q R + <R Q S = 180

Given

<R Q S =x+1

<P Q R = 3x-5

Substitute the given expression into the formula and calculate x;

3x-5+x+1 = 180

collect like terms

3x+x - 5+1 = 180

4x-4 = 180

4x = 180+4

4x = 184

divide both sides by 4

4x/4 = 184/4

x = 46°

To get m∠PQR, we will substitute x = 46 into the expression for m∠PQR.

m∠PQR = 3x-5

m∠PQR = 3(46) - 5

m∠PQR = 138 - 5

m∠PQR = 133°

Hence the measure of angle m∠PQR is 133°

4 0

3 years ago

Can a triangle be formed with the side lengths of 2.9 in, 4.8 in, and 7.4 in?

ddd [48]

Answer: Yes

Step-by-step explanation: A triangle can be formed because A+B>C

A and B are 2.9 and 4.8

Since those numbers have the least value

I added both and found that A and B are equal to 7.7

7.7>7.4

These sides could form a triangle

6 0

3 years ago

Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?

BaLLatris [955]

Answer:

$Vertex = (\frac{1}{2},\frac{7}{4})$

Step-by-step explanation:

Given

$f(x) = x^2 - x +2$

Required

The vertex

We have:

$f(x) = x^2 - x +2$

First, we express the equation as:

$f(x) = a(x - h)^2 +k$

Where

$Vertex = (h,k)$

So, we have:

$f(x) = x^2 - x +2$

--------------------------------------------

Take the coefficient of x: -1

Divide by 2: (-1/2)

Square: (-1/2)^2

Add and subtract this to the equation

--------------------------------------------

$f(x) = x^2 - x +2$

$f(x) = x^2 - x + (-\frac{1}{2})^2+2 -(-\frac{1}{2})^2$

$f(x) = x^2 - x + \frac{1}{4}+2 -\frac{1}{4}$

Expand

$f(x) = x^2 - \frac{1}{2}x- \frac{1}{2}x + \frac{1}{4}+2 -\frac{1}{4}$

Factorize

$f(x) = x(x - \frac{1}{2})- \frac{1}{2}(x - \frac{1}{2})+2 -\frac{1}{4}$

Factor out x - 1/2

$f(x) = (x - \frac{1}{2})(x - \frac{1}{2})+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{8 -1 }{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{7}{4}$

Compare to: $f(x) = a(x - h)^2 +k$

$h = \frac{1}{2}$

$k = \frac{7}{4}$

Hence:

$Vertex = (\frac{1}{2},\frac{7}{4})$

8 0

3 years ago

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