AE x BE = DE x CE
6x5 = 30
6 x DE = 30
DE = 30/6 =5
DC = DE +CE = 5+6 =11
Answer is C) 11
Answer:
30 basketballs
Step-by-step explanation:
one layer would be 3 x 2 = 6
- to find how much you would need to cover the bottom of the locker, you would use the numbers 3 and 2, then multiply them and you get 6. You would need 6 basketballs to cover the bottom of the locker. That would be your first layer
5 layers would be 6 x 5 = 30
- So the bottom would be filled with 6 basketballs. Now since the locker is 5 feet high multiply 6 x 5 and that would get you your total of basketballs
5/12 + 3/12 = 8/12
8/12 of the games are either sports or educational.
Why not draw the graph of y=|x|? It has a v-shape, and the vertex is at (0,0).
The graph of f(x) = |x| - 3 looks exactly the same, EXCEPT that the whole graph of |x| is shifted 3 units downward. The smallest value that y can have is therefore -3.
Can you now figure out the range of f(x)?
There are 37 jelly beans so p for the first one is 27/37. That leaves 36 in the bag. So p for the second jelly bean is 10/36=5/18.
The combine probability is 27/37×5/18=3/37×5/2=15/74.
