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Butoxors [25]
3 years ago
6

Need help :((((((((((

Mathematics
2 answers:
Ksivusya [100]3 years ago
8 0

The correct answer is D. 2s + 3

Hope this helps!

Mnenie [13.5K]3 years ago
6 0
The answer is D 2s + 3
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Grace [21]
\Omega=\{1;\ 2;\ 3;\ 4;\ 5;\ 6;\ 7;\ 8;\ 9;\ 10\}\\\\|\Omega|=10\\\\A=\{1;\ 3;\ 6;\ 7\};\ B=\{2;\ 3\}\\\\A\ \cup\ B=\{1;\ 2;\ 3;\ 6;\ 7\}\\\\|A\ \cup\ B|=5\\\\P(A\ \cup\ B)=\dfrac{|A\ \cup\ B|}{|\Omega|}\to P(A\ \cup\ B)=\dfrac{5}{10}=\dfrac{1}{2}=0.5=0.50
4 0
2 years ago
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I NEED HELP PLEASE AND SHOW THE WORK PLEASE
Trava [24]

Answer:

6. x = 28 degrees

7.  z = 1.6 cm

Step-by-step explanation:

6.  

Notice that you can use the property that tells us that the addition of all internal angles of a triangle must give 180 degrees, then you write the following equation:

50 + 69 + (2 x +5) = 180

combine like terms:

119 + 2 x + 5 = 180

124 + 2 x = 180

subtract 124 from both sides:

2 x = 56

divide by 2 both sides:

x = 56 / 2

x = 28 degrees

Problem 7.

If the two triangles are congruent, then the side MN must equal side RS.

Since MN  measure 1,8 cm, then RS must also measure 1.8 cm

and we can write the equation:

1.8 = 3 z - 3

adding 3 to both sides:

1.8 + 3 = 3 z

4.8 = 3 z

dividing both sides by 3:

z = 4.8 / 3

z = 1.6 cm

8 0
2 years ago
I know that the surface area is equal to 264 but I need to know how to get there (the steps)
Ray Of Light [21]
You posted the question twice ... I have repeated the answer here .. .

Find the area of all the sides:
10 x 9 = 90
9 x 8 = 72
1/2 x 6 x 8 = 24
1/2 x 6 x 8 = 24
6 x 9 = 54

Add them up:
90 + 72 + 24 + 24 + 54 = 264 square metres
7 0
2 years ago
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Now, ONLY look at the shortest 8 people (on the left, from Snooki 57 inches to Miley Cyrus 65 inches). Can you find the median h
Kryger [21]

Answer: 60.875

Step-by-step explanation:

57+59+60+60+61+61+64+65= 487

then 487/8= 60.875

7 0
2 years ago
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Solve the system of linear equations by substitution.<br><br> 8x−13y=0<br><br> 12x+3=y
kogti [31]
X=-0.61 and Y is 4 is I did my math right
7 0
3 years ago
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