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3 years ago

Need help :((((((((((

Mathematics

2 answers:

Ksivusya [100]3 years ago

8 0

The correct answer is D. 2s + 3

Hope this helps!

Mnenie [13.5K]3 years ago

6 0

The answer is D 2s + 3

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What is the property of 11+0=11?

dangina [55]

$Zero \: Property \: of \: Multiplication \\\: = a \times 0 = 0$

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2 years ago

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Help me with this if anyone can! Please and thank you

Valentin [98]

ANSWER

$y = 3x - 3$

EXPLANATION

Let

$y = mx + c$

be the equation.

We can choose any two ordered pairs to determine the equation of the relation.

$(6,15) \: and \: (8,21)$

We find m using the formula;

$m = \frac{y_2-y_1}{x_2-x_1}$

$m = \frac{21 - 15}{8 - 6} = \frac{6}{2} = 3$

The equation becomes

$y = 3x + c$

When x=6, y=15.

This implies that,

$15 = 3(6) + c$

$15= 18 + c$

$15 - 18= c$

$c = -3$

The equation of the relation is therefore,

$y = 3x -3$

3 0

4 years ago

Mr. Rico's small business is starting to make a profit. His costs last week were -$352. His profit last week was $22. How many t

MrRa [10]

Answer:

The Answer is -16

Step-by-step explanation:

The equation to this would be -352 / 22, which would give you 16, hope this helped!

5 0

3 years ago

X -y = 3<br><br><br> solve for y

nirvana33 [79]

Answer:

y= -3+x

Step-by-step explanation:

hope this helps :)

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3 years ago

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The caller times at a customer service center has an exponential distribution with an average of 22 seconds. Find the probabilit

jenyasd209 [6]

Answer:

The probability that a randomly selected call time will be less than 30 seconds is 0.7443.

Step-by-step explanation:

We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.

Let X = caller times at a customer service center

The probability distribution (pdf) of the exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} ; x > 0$

Here, $\lambda$ = exponential parameter

Now, the mean of the exponential distribution is given by;

Mean = $\frac{1}{\lambda}$

So, $22=\frac{1}{\lambda}$ ⇒ $\lambda=\frac{1}{22}$

SO, X ~ Exp( $\lambda=\frac{1}{22}$ )

To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;

$P(X\leq x) = 1 - e^{-\lambda x}$ ; x > 0

Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)

P(X < 30) = $1 - e^{-\frac{1}{22} \times 30}$

= 1 - 0.2557

= 0.7443

7 0

4 years ago