Answer:
-1
Step-by-step explanation:
First, find g(3), g(3) is 5.
Next, plug in 5 for g(3).
So we have f(5), f(5) is -1
In this question, <span>q is the number of buggies the company can sell in a month if the price is $p per buggy. The revenue should be number of buggies sold(q) multiplied by the price(p). The equation would be:
revenue= p * q
revenue= p * (-4p + 616)= -4p^2 + 616p
The maximum revenue should be in the peak of the graph. The calculation would be:
</span>-4p^2 + 616p
-4*2 p^2-1 + 616*1 p^1-1=0
<span>-8p + 616=0
8p= 616
p=77
Put p=77 in the revenue equation would result
</span>revenue= -4p^2 + 616p
revenue= -4(77^2) + 616(77) = -23716 + 47432= $23716
Answer:
b
Step-by-step explanation:
b makes the most sense out of all of them
Answer:
3x(x^2+3x-5) - factorised
Step-by-step explanation:
