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Sveta_85 [38]
3 years ago
8

What is the vertex of y=x^2+4x+3

Mathematics
1 answer:
AnnyKZ [126]3 years ago
7 0

Answer:

(-2, -1)

Step-by-step explanation:

This is a quadratic equation in standard form, and a = 1, b = 4 and c = 3.

The x-coordinate of the vertex is given by the formula

        -b                                                                         -4

x = --------- which here has the numerical value x = -------- = -2

        2a                                                                           2

Finally, we evaluate y=x^2+4x+3 at x = -2 to find the y-coordinate of the vertex:

y = (-2)^2 + 4(-2) + 3 = -1

The vertex is at (-2, -1).

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\displaystyle \large{[ - 10i+ 21  - 24 {i}^{2} ]- (2 - 3i)}

<u>I</u><u>m</u><u>a</u><u>g</u><u>i</u><u>n</u><u>a</u><u>r</u><u>y</u><u> </u><u>U</u><u>n</u><u>i</u><u>t</u>

\displaystyle \large{i =   \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2}  =   - 1 }

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\displaystyle \large{[ - 10i+ 21  - 24  ( - 1) ]- (2 - 3i)}  \\   \displaystyle \large{[ - 10i+ 21   + 24]- (2 - 3i)}  \\   \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}

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