<span>30 hours
For this problem, going to assume that the actual flow rate for both pipes is constant for the entire duration of either filling or emptying the pool. The pipe to fill the pool I'll consider to have a value of 1/12 while the drain that empties the pool will have a value of 1/20. With those values, the equation that expresses how many hour it will take to fill the pool while the drain is open becomes:
X(1/12 - 1/20) = 1
Now solve for X
X(5/60 - 3/60) = 1
X(2/60) = 1
X(1/30) = 1
X/30 = 1
X = 30
To check the answer, let's see how much water would have been added over 30 hours.
30/12 = 2.5
So 2 and a half pools worth of water would have been added. Now how much would be removed?
30/20 = 1.5
And 1 and half pools worth would have been removed. So the amount left in the pool is
2.5 - 1.5 = 1
And that's exactly the amount needed.</span>
Answer is
x > 5
Tell me if it helps
Answer:
parallel
Step-by-step explanation:
Solve both equations for y to make it easier to compare them.
2x - 5y = 0 ↔ 5y = 2x, or y = (5/2)x.
y = (5/2)x - 3
Since the slopes are the same, the two lines are parallel.
Answer by JKismyhusbandbae: expression 2 and expression 1
Look at the four expressions. Simplify any expressions that can be simplified to see which two are equivalent.
8v × 30v = ( 8 × 30) × ( v × v) = 
Since expression 2 can be simplified to expression 1, they are equivalent.
It is zero
the answer is 5.3 x 10^0
because 10^1 would force you to move the decimal place to make it 53
I hope this helps!
