Answer:
0.7361
Step-by-step explanation:
In this question we have
number to be 10
Then we have a probability of 10% = 0.10
We have q = 1-p
= 1-0.10 = 0.90
Then the probability of not more than 1 being defective:
P(x=0) + p(x= 1)
(10C0 x 0.1⁰ x 0.9^10-0)+(10C1 x 0.1¹ x 0.9^10-1)
= 1 x1 x0.3487 + 10 x 0.1 x 0.3874
= 0.3487 + 0.3874
= 0.7361
This is the the required probability and this answers the question.
probability = 10 percent = 0.1
q= 1- 10percent = 90% = 0.9
n = 4
To get the required probabiltiy for this question is
P(not greater than one is defective )=P(x=0)+P(x=1)
= 4C0x(0.1)⁰x(0.9)⁴+4C1x(0.1)¹x(0.9)³
= 0.9477
The required probability is 0.9477
<em>The </em><em>value</em><em> </em><em>of</em><em> </em><em>u</em><em> </em><em>is</em><em> </em><em>-</em><em>3</em><em>4</em><em>3</em>
<em>pl</em><em>ease</em><em> see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>
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<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
The answer is A) 7x103 is 3.5 times larger than 2x103
Ok so what u do first is
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A
<u>Answer:</u> 90%
<u>Reasoning:</u> To solve this divide 18 by 20
18/20= 0.9
Now multiply 20 by 0.9 to check
20 x 0.9= 18
