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postnew [5]
3 years ago
14

The doctor has told Cal O'Ree that during his ten weeks of working out at the gym, he can expect each week's weight loss to be $

1\%$ of his weight at the end of the previous week. His weight at the beginning of the workouts is $244$ pounds. How many pounds does he expect to weigh at the end of the ten weeks?
Mathematics
1 answer:
Sergio [31]3 years ago
6 0

Answer:

220.67 pounds

Step-by-step explanation:

This problem can be treated as a compounded interest with a weekly rate of -1%. Cal's weight after 'n' weeks at a 1% loss rate per week is described by the following expression:

W = 244*(1-0.01)^n

For n = 10 weeks, Cal's weight is:

W = 244*(1-0.01)^{10}\\W=220.67\ pounds

He expects to weigh 220.67 pounds at the end of the ten weeks.

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Ella has 0.5 lbs of sugar. How much water should she add to make the following concentrations? Tell Ella how much syrup she will
HACTEHA [7]

Ella has to add 32.833 lbs of water to get 33.333 lbs of syrup.

<u>Solution:</u>

Ella has 0.5 lbs of sugar. Let x lbs be the amount of water Ella should add to get the 1.5% of syrup,

\Rightarrow0.5\text{ lbs }- 1.5\%

\Rightarrow x+0.5\text{ lbs }- 100\%

On writing the proportion,

\Rightarrow\dfrac{0.5}{x+0.5}=\dfrac{1.5}{100}\\ \\\Rightarrow0.5\cdot 100=(x+0.5)\cdot 1.5\\ \\\Rightarrow50=1.5x+0.75\\ \\\Rightarrow1.5x=50-0.75\\ \\\Rightarrow1.5x=49.25\\ \\\Rightarrow x=\dfrac{49.25}{1.5}\approx 32.833\ lbs

To get 1.5% syrup Ella should add 32.833 lbs of water. The total weight of syrup is 33.333 lbs.

7 0
3 years ago
Oceanside Bike Rental Shop charges a sixteen dollar fixed fee plus six dollars an hour for renting a bike. Dan paid fifty two do
bearhunter [10]
$52 - $16= $36
$36/6 = 6 hours
8 0
3 years ago
Plsssss helppp meeeee
Zinaida [17]

Answer:

10

Step-by-step explanation:

7+15/5

4 0
3 years ago
Read 2 more answers
Pls help asap whats the local min value of the function below?
shutvik [7]

Answer:

<em>given function has 2 minimums</em> - \frac{9}{4}  and  \frac{9}{4}  

Step-by-step explanation:

<u><em>Step 1.</em></u> g'(x) = 4x³ - 10x

<u><em>Step 2.</em></u> Find find the critical points:

4x³ - 10x = 2x(2x² - 5) = 0

x_{1} = - \sqrt{\frac{5}{2} } , x_{2} = 0 , x_{3} = \sqrt{\frac{5}{2} }

<u><em>Step 3.</em></u> g'(x) > 0 :  - \sqrt{\frac{5}{2} } < x < 0  or  x > \sqrt{\frac{5}{2} }

g'(x) < 0 :   x < - \sqrt{\frac{5}{2} }   or   0 < x < \sqrt{\frac{5}{2} }

<u><em>Step 4.</em></u>

If x ∈ ( - ∞ , - \sqrt{\frac{5}{2} } ) , g(x) is decreasing ;

If x = - \sqrt{\frac{5}{2} } , g(x) has <em>minimum</em> value ;

If x ∈ ( - \sqrt{\frac{5}{2} } , 0 ) , g(x) is increasing ;

If x = 0 , g(x) has maximum value ;

If x ∈ ( 0 , \sqrt{\frac{5}{2} } ) , g(x) is decreasing ;

If x = \sqrt{\frac{5}{2} } , g(x) has <em>minimum</em> value ;

If x ∈ ( \sqrt{\frac{5}{2} } , ∞ ) , g(x) is increasing .

⇒ at ( - \sqrt{\frac{5}{2} } , - \frac{9}{4} ) and at ( \sqrt{\frac{5}{2} } , \frac{9}{4} ) , g(x) reaches its minimum

8 0
3 years ago
PLZ HELPP!! Compare the two functions. Which statement is true?
pav-90 [236]

Answer:

statement C

Step-by-step explanation:

8 0
3 years ago
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