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Softa [21]
3 years ago
12

What is the following product? Assume y >/= 0

Mathematics
2 answers:
spin [16.1K]3 years ago
7 0
\sqrt{y^3} * \sqrt{y^3}= \sqrt{y^3*y^3}= \sqrt{y^6}=y^{ \frac{6}{2} } =y^3
svp [43]3 years ago
4 0
\sqrt{y^{2} *y} * \sqrt{ y^{2}*y } 

y* \sqrt{y} *y* \sqrt{y} 

y*y*y
y^{3}
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Solve: -5y- 9 = -(y - 1)
RoseWind [281]

Answer:

Exact Form:

y=-\frac{5}{2}

6 0
2 years ago
Read 2 more answers
The quotient of 15 and n is 5
Anna35 [415]

My English is not that great but if I got it right the answer is 3

7 0
2 years ago
Which function equation is represented by the graph?
Drupady [299]
The correct answer is C. <span>f(x)=20(35)x</span>
8 0
3 years ago
Let f(X)=3√x
SOVA2 [1]

g(x) = 3√(x-5) -1

The process of altering a graph to produce a different version of the preceding graph is known as graph transformation. The graphs can be moved about the x-y plane or translated. They may also be stretched, or they may undergo a mix of these changes.

Horizontal stretching: It means the graph is elongated or shrink in x direction.

Vertical stretching : It means the graph is elongated or shrink in y direction

Vertical translation : It means moving the base of the graph in y direction

Horizontal translation : It means moving the base of the graph in x direction

According to rules of transformation f(x)+c shift c units up and f(x)-c shift c units down.

Therefore, in order to  move the graph down 1 units, we need to subtract given function by 1 , we get

g(x) = 3√x -1

According to rules of transformation f(x+c) shift c units left and f(x-c ) shift c units right.

Therefore, in order to  move the graph left by 5 units, we need to add given function by 5 , we get

g(x) = 3√(x-5) -1

To learn more about graphical transformation,  refer to brainly.com/question/4025726

#SPJ9

4 0
1 year ago
If m&lt;1=6x+50 and m&lt;2=4x+40 find x
Pepsi [2]
\text{Adjacent angles on a straight line sum up to 180} \textdegree

\text{Therefore }\measuredangle 1 + \measuredangle 2 = 180 \textdegree

\text {Since } \measuredangle 1 = 6x+50 \text { and } \measuredangle 2 = x+40

(6x+50)  + (4x+40) = 180

6x+50 + 4x+40 = 180

10x+90 = 180

10x = 180 - 90

10x = 90

x = 9

Answer: x = 9
8 0
3 years ago
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