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4 years ago

What is the following product? Assume y >/= 0

Mathematics

2 answers:

spin [16.1K]4 years ago

7 0

$\sqrt{y^3} * \sqrt{y^3}= \sqrt{y^3*y^3}= \sqrt{y^6}=y^{ \frac{6}{2} } =y^3$

svp [43]4 years ago

4 0

$\sqrt{y^{2} *y} * \sqrt{ y^{2}*y } 
$
$y* \sqrt{y} *y* \sqrt{y} 
$
$y*y*y$
$y^{3}$

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Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle R? You must show all work and calcu

Radda [10]

You can inscribe a quadrilateral inside a circle if and only if its opposite angles are supplementar. In your case, this means that

$\hat{O} + \hat{Q} = \hat{R} + \hat{P} = 180^\circ$

Since we're interested in the angle R, let's use the second part of the equalities above to substitute the given values for R and P:

$\hat{R} + \hat{P} = 3y+8+y = 180^\circ$

The left hand side can be simplified to $4y+8$ , so if we subtract 8 from both sides the equation becomes

$4y = 172 \implies y = \cfrac{172}{4} = 43$

Since $y = 3$ , we can compute the angle R by plugging this value into its formula:

$R = 3y+8 = 3\cdot 43 + 8 = 129+8 = 137$

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3 years ago

Can any one please help me under this? I need to know which option indicates that 3 goes after 5and between 7,12and 5 then how t

Archy [21]

"3 va después de 5 y entre 7 y 12" = "3 goes after 5, and between 7 and 12"

This eliminates A and D (3 is not between 7 and 12 in either choice).

"5 va antes de 12 y entre 7 y 3" = "5 goes after 12, and between 7 and 3"

This eliminates C (5 is not between 7 and 3).

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2 years ago

Resolving inequalities 6/5x-12<2-3/2x

Anna007 [38]

Answer: x < $\frac{140}{27}$

Step-by-step explanation:

$\frac{6}{5}x - 12 < 2 - \frac{3}{2}x$

$10(\frac{6}{5}x - 12) < 10(2 - \frac{3}{2}x)$

2(6)x - 10(12) < 10(2) - 5(3)x

12x - 120 < 20 - 15x

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+120 +120

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$\frac{27x}{27} < \frac{140}{27}$

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