2 years ago

At what points do the the graphs of y = 2x+1 and y= -(x-1)^2+3 intersect?

Mathematics

1 answer:

Umnica [9.8K]2 years ago

7 0

The answer would be B. (-1,-1) and (1,3)

Hope that helped

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3 years ago

Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000

zvonat [6]

Answer:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

$A = \int\limits^t_ {1} \,{13\cdot x^{3}} dx$

$A = 13 \int\limits^t_1 {x^{3}} \, dx$

$A = \frac{13}{4}\cdot (t^{4}-1)$

Evaluated areas are presented below:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

8 0

3 years ago