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3 years ago

Please answer asap no work needed :)

Mathematics

2 answers:

Marat540 [252]3 years ago

3 0

Answer:

2x+12 simplified is x+4

ddd [48]3 years ago

3 0

X+4 is the answer I think

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A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The

lianna [129]

Answer:

34 N.

Step-by-step explanation:

Net force in x direction = 65 cos 58

= 34 N.

4 0

3 years ago

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On the coordinate plane, what quadrant is the point (1 , 4) located in?

Gemiola [76]

Answer:

on the second one

Step-by-step explanation:

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3 years ago

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Law of cosines: a2 = b2 + c2 – 2bccos(A) Find the measure of Q, the smallest angle in a triangle whose sides have lengths 4, 5,

Ierofanga [76]

We are tasked to solve for the smallest angle using the law of cosines given that the three sides of the triangle are 4,5 and 6.
a=4 , b=5, c=6
Angle 1:
cosA = 5² + 6² - 4² / 2*5*6
A=41.41°

Angle 2:
cos B = 4²+6² -5² /2*4*6
B= 55.77°

Angle C:
C = 180° - 41.41° - 55.77°
C = 82.82°

The smallest angle is A which is equal to 41.41°.

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4 years ago

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The water height of a pool is determined by 5g2 + 3g − 2, the rate that the pool is filled, and 6g2 − 4g − 3, the rate that wate

lyudmila [28]

Answer:

$h_g=-g^2+7g+1\\\\h_1=7\\\\h_2=11\\\\h_3=13\\\\h_4=13$

Step-by-step explanation:

Given the rate of filling is $5g^2+3g-2$ and the rate of emptying the pool is $6g^2-4g-3$ . The height of the pool at any time is:

$h_t=R_{in}-R_{out}, h_t- \ height \ at\ time\ t\\\\h_t=(5g^2+3g-2)-(6g^2-4g-3)\\\\h_t=-g^2+7g+1$

#Substitute the value of g in the height equation to find the height of the pool:

#g=1

$h_t=-g^2+7g+1, \ g=1\\\\h_t=-(1)^2+7(1)+1\\\\=7$

#g=2

$h_t=-g^2+7g+1, \ g=1\\\\h_t=-(2)^2+7(2)+1\\\\=11$

#g=3

$h_t=-g^2+7g+1, \ g=1\\\\h_t=-(3)^2+7(3)+1\\\\=13$

#g=4

$h_t=-g^2+7g+1, \ g=1\\\\h_t=-(4)^2+7(4)+1\\\\=13$

6 0

4 years ago

Review the proof.

andrezito [222]

Answer:

Step-by-step explanation:

A 2-column table with 8 rows. Column 1 is labeled Step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine (2 x) = 1 minus 2 sine squared (x), let 2 x = theta, then x = StartFraction theta Over 2 EndFraction, cosine (theta) = 1 minus 2 sine squared (StartFraction theta Over 2 EndFraction), negative 1 + cosine (theta) = negative 2 sine squared (StartFraction theta Over 2 EndFraction), 1 + cosine (theta) = 2 sine squared (StartFraction theta Over 2 EndFraction), StartFraction 1 minus cosine (theta) Over 2 EndFraction = sine squared (StartFraction theta Over 2 EndFraction), sine (StartFraction theta Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 minus cosine (theta) Over 2 EndFraction EndRoot.

Which step contains an error?

Answer:

Step-by-step explanation:

7 0

3 years ago

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