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Cerrena [4.2K]
3 years ago
9

Help plzzzzzz! Sandy works at a clothing store. She makes $9 per hour plus earns 10% commission on her sales. She worked 72 hour

s over the last two weeks and had a total of $2,905 in sales before taxes. Which of the following is closest to how much she will earn in hourly wages and commission for those two weeks?
Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

Step-by-step explanation:

Payment per hour is $8

commission is 15%

Total number of hours worked for 2 weeks is 73 hours

Total sales=$2095

commission earned for 2 weeks:

15/100×2095

=$314.25

Total amount earned in 73 hours:

73×8=$584

Total amount earned in commission and wages:

584+314.25

=$898.25

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Hello again! This is another Calculus question to be explained.
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Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Functions

  • Function Notation
  • Exponential Property [Rewrite]:                                                                   \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Property [Root Rewrite]:                                                           \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

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Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

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Step-by-step explanation:

We are given the following and are trying to find the second derivative at <em>x</em> = 2:

\displaystyle f(2) = 2

\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

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When we differentiate this, we must follow the Chain Rule:                             \displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]

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