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olga nikolaevna [1]
3 years ago
9

Which of the following statements about absolute value is not true?

Mathematics
1 answer:
Dmitry [639]3 years ago
7 0

Step-by-step explanation:

A. Absolute value is the sign of the number.

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Im kinda confused on this. i need help.​
RideAnS [48]

<u>Given </u><u>:</u><u>-</u>

  • A graph is given to us .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The equation in slope intercept form .

<u>Answer</u><u> </u><u>:</u><u>-</u>

From the given graph , we can see that the line passes through y axis at (0,5) . So the y intercept is 5 . And the slope of the line is 5/2 = 2.5 . So ,

\sf\longrightarrow y intercept = 5 .

\sf\longrightarrow slope = 5/2 .

Now here we can use the slope intercept form as ,

\sf\longrightarrow y = mx + c

\sf\longrightarrow y = 5/2x + 5

<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>y </u><u>=</u><u> </u><u>5</u><u>/</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>5</u><u>.</u>

4 0
2 years ago
Read 2 more answers
HELP 40 POINTS
Tom [10]
Answer: the function g(x) has the smallest minimum y-value.


Explanation:


1) The function f(x) = 3x² + 12x + 16 is a parabola.


The vertex of the parabola is the minimum or maximum on the parabola.


If the parabola open down then the vertex is a maximum, and if the parabola open upward the vertex is a minimum.


The sign of the coefficient of the quadratic term tells whether the parabola opens upward or downward.


When such coefficient is positive, the parabola opens upward (so it has a minimum); when the coefficient is negative the parabola opens downward (so it has a maximum).


Here the coefficient is positive (3), which tells that the vertex of the parabola is a miimum.


Then, finding the minimum value of the function is done by finding the vertex.

I will change the form of the function to the vertex form by completing squares:

Given: 3x² + 12x + 16

Group: (3x² + 12x) + 16
Common factor: 3 [x² + 4x ] + 16
Complete squares: 3[ ( x² + 4x + 4) - 4] + 16
Factor the trinomial: 3 [(x + 2)² - 4] + 16
Distributive property: 3 (x + 2)² - 12 + 16
Combine like terms: 3 (x + 2)² + 4

That is the vertex form: A(x - h)² + k, whch means that the vertex is (h,k) = (-2, 4).


Then the minimum value is 4 (when x = - 2).


2) The othe function is <span>g(x)= 2 *sin(x-pi)
</span>

The sine function goes from -1 to + 1, so the minimum value of sin(x - pi) is - 1.


When you multiply by 2, you just increased the amplitude of the function and obtain the new minimum value is 2 (-1) = - 2


Comparing the two minima, you have 4 vs - 2, and so the function g(x) has the smallest minimum y-value.

7 0
3 years ago
HELP THIS IS DUE SOON PLEASEEEEEEEEEEEE HELPPPPPPPPPP
muminat

Answer:

6x^2 + 4x

Step-by-step explanation:

g(x) + f(x)

= -8x^2 - 3x + 5 + 2x^2 + 7x - 5

= -8x^2 + 2x^2 - 3x + 7x + 5 - 5

= - 6x^2 + 4x

4 0
3 years ago
A math class is having a discussion on how to determine if the expressions 4 x minus x + 5 and 8 minus 3 x minus 3 are equivalen
Brut [27]

Answer:

  • Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.

Step-by-step explanation:

<u>Given expressions</u>

  • 4x - x + 5 = 3x + 5
  • 8 - 3x - 3 = -3x + 5

Compared, we see the expressions are different as 3x and -3x have different coefficient

<u>Answer options</u>

Both expressions should be evaluated with one value. If the final values of the expressions are both positive, then the two expressions must be equivalent.

  • Incorrect. Positive outcome doesn't mean equivalent

----------------------------------------

Both expressions should be evaluated with one value. If the final values of the expressions are the same, then the two expressions must be equivalent.

  • Incorrect. There are 2 values- variable and constant

----------------------------------------

Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are positive, then the two expressions must be equivalent.

  • Incorrect. Positive outcome doesn't mean equivalent.

----------------------------------------

Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.

  • Correct.  
3 0
3 years ago
Gisselle has 1/2 of a candy bar. She role off 1/2 of what she had. She then took the piece she broke off and split it into three
saul85 [17]

Answer:

\frac{1}{12}

Step-by-step explanation:

Given:

Gisselle has 1/2 of a candy bar.

She role off 1/2 of what she had and split it into three equal pieces.

Question asked:

What fraction of a candy bar was each piece?

Solution:

Gisselle has = \frac{1}{2} \ of \ a \ candy \ bar

She role off = \frac{1}{2} \ of \ what\ she \ had

                     =\frac{1}{2}  \ of\  \frac{1}{2}\\=\frac{1}{2} \times \frac{1}{2}\\\\=\frac{1}{4}

As she split it into three equal pieces, we will divided it by 3, we get,

\frac{1}{4} \div3\\\frac{1}{4}\times\frac{1}{3}

\frac{1}{12}

Therefore, fraction of a candy bar of each piece is \frac{1}{12}

4 0
2 years ago
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