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kenny6666 [7]
2 years ago
6

Need help with question 15

Mathematics
1 answer:
OLga [1]2 years ago
6 0
I hope this helps you

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How do you multiply fractions and express product in simplestform.
vagabundo [1.1K]
You just multiply top times top and bottom times bottom and then find a number you can divide into the number and you keep doing that until you can't simplify any more.
3 0
3 years ago
Find the value of each expression.<br> 6b2 – 5 if b = 3
snow_tiger [21]
The answer should be 31, if I’m doing this correctly.
6(3)2-5 (multiply 6 and 3, you get 18)
18(2)-5 (multiply 18 and 2, you get 36)
36-5 (subtract 36 and 5)
31
3 0
3 years ago
Read 2 more answers
What is the probability of picking a blue coin out of a bag that contains 5 blue and 10 red coins
Neko [114]

the probability is 5/15 or 1/3.

You add up all the coins (5+10=15) and since there’s 5 blue coins in the bag, you put 5 over 15. You simplify that to 1/3.

hope this helped !!

6 0
3 years ago
What is the quotient when 4x3 + 2x + 7 is divided by x + 3?
Arte-miy333 [17]

Answer:

The quotient of this division is (4x^2 -12x + 38). The remainder here would be -26.

Step-by-step explanation:

The numerator 4x^3 + 2x + 7 is a polynomial about x with degree 3.

The divisor x + 3 is a polynomial, also about x, but with degree 1.

By the division algorithm, the quotient should be of degree 3 - 1 = 2, while the remainder shall be of degree 1 - 1 = 0 (i.e., the remainder would be a constant.) Let the quotient be a\,x^2 + b\, x + c with coefficients a, b, and c.

4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3).

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is 4 x^3. On the right-hand side, that would be a\, x^3. Hence a = 4.

Now, given that a = 4, rewrite the right-hand side:

\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}.

Hence:

4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)

Subtract \left(4x^3 + 12x^2\right from both sides of the equation:

-12x^2 + 2x + 7 = (b\,x + c)(x + 3).

The term with a degree of two on the left-hand side has coefficient (-12). Since the only term on the right hand side with degree two would have coefficient b, b = -12.

Again, rewrite the right-hand side:

\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}.

Subtract -12x^2 -36x from both sides of the equation:

38x + 7 = c(x + 3).

By the same logic, c = 38.

Hence the quotient would be (4x^2 - 12x + 38).

6 0
3 years ago
Which image is a reflection of the orange letter K in Quadrant I?
stellarik [79]

Answer: Quadrant 4

Step-by-step explanation:

pls give brainliest

have a nice day!

6 0
1 year ago
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