The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.
<h3>What are the proves?</h3>
1. To know collinear vectors:
∧ ⁻a ║ ⁻a
If ⁻b = ∧ ⁻a
then |⁻b| = |∧ ⁻a|
So one can say that line ⁻b and ⁻a are collinear.
2. If ⁻a and ⁻b are collinear
Assuming |b| length is 'μ' times of |⁻a |
Then | 'μ' ⁻a| = | 'μ' ⁻a|
So ⁻b = 'μ' ⁻a
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1.5y < -6.75
First, divide both sides by '1.5'.
Second, since 4.5 × 1.5 = 6.5, simplify the fraction to '-4.5'
Answer:
y < -4.5
Hm. So if the problem is x+33=29, <span><span>x+33</span>−33</span>=<span>29−33 </span><span>x=<span>−<span>4</span></span></span>
Answer:
The solution is x = 1/log(6)
Step-by-step explanation:
Hi there!
First, let´s write the equation:
6ˣ + 2 = 12
subtract 2 at both sides of the equation
6ˣ = 10
apply log at both sides of the equation
log(6ˣ) = log(10) log(10) = 1
Apply logarithm property: log(xᵃ) = a log(x)
x log(6) = 1
Divide both sides by log(6)
x = 1/log(6)
The solution is x = 1/log(6)
Have a nice day!