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3 years ago

Simplify using the distributive property 4(7 - 2)

Mathematics

1 answer:

solmaris [256]3 years ago

4 0

Answer:

28-8 is the answer simplified but not yet complete

20 is the final answer

Step-by-step explanation:

Hope this helps :)

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Enter the fraction 33100 as a decimal

Mariulka [41]

Answer:

0.33

Step-by-step explanation:

If you have the number 1 and divide it by 100, you get 1/100, 0.01, or 1% of 1. If you multiply 1/100 by 33, you get 33/100, 0.33, or 33% of 1.

7 0

3 years ago

Read 2 more answers

A school wishes to accept 2000 students for their freshman class, and they expect 20,000 applications. In order to make their ad

vovangra [49]

Answer:

456

Step-by-step explanation:

Let X be the SATscore scored by the students

Given that X is normal (1000,200)

By converting into standard normal variate we can say that

$z=\frac{x-1000}{200}$ is N(0,1)

To find the top 10% we consider the 90th percentile for z score

Z 90th percentile = 1.28

$X= 200+1.28(200)\\= 200+256\\=456$

i.e. only students who scored 456 or above only should be considered.

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3 years ago

MORE PINTS LOLOLOLOLOOLOLLOLOLOLOLOLOLOLOLO

vladimir2022 [97]

Answer:

mmm

Step-by-step explanation:

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2 years ago

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The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.85}{2} = 0.075$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.075 = 0.925$ , so Z = 1.44.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that $\sigma = \sqrt{1.69} = 1.3$

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.14 = 1.44\frac{1.3}{\sqrt{n}}$

$0.14\sqrt{n} = 1.44*1.3$

$\sqrt{n} = \frac{1.44*1.3}{0.14}$

$(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2$

$n = 178.8$

Rounding up

A sample of 179 is needed.

7 0

3 years ago

The sum of two numbers is 72 while the difference between the numbers is 25. the larger of the numbers is

7nadin3 [17]

2 equations: the first one is the sum of 2 unknown numbers x and y: x + y = 72. Now the difference is 25, so x - y = 25. Solve the first equation for y: y = 72 - x. Sub that into the second equation to solve for x: x - (72 - x) = 25. x - 72 + x = 25 and 2x - 72 = 25. Therefore, 2x = 97 and x = 48.5 That's the larger of the 2 numbers; since we subtracted y from x we defined x as the larger of the 2. Just for fun, plug x in to find that y = 23.5

7 0

3 years ago

Simplify using the distributive property 4(7 - 2)​

Simplify using the distributive property 4(7 - 2)