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aniked [119]
3 years ago
6

What is 51/2 × 21/3?

Mathematics
2 answers:
HACTEHA [7]3 years ago
8 0
D)12 5/6 hope this helped
bixtya [17]3 years ago
3 0
5 1/2×2 1/3
5 1/2=11/2
2 1/3=7/3
11/2×7/3=77/6
77/6= 12 5/6

The answer is D.
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Noah is buying a pair of jeans and using a coupon for 10%off. The total price is $56.70 which includes $2.70 in sales tax. Noah’
lora16 [44]

Answer:

See below.

Step-by-step explanation:

So, we know that Noah's purchase can be modeled by the equation:

x-0.1x+2.70=56.70

Part 1)

The solution to the equation will be the value of x.

In this case, x will represent the original price of the jeans.

We know that Noah has a coupon for 10% off the <em>original price of the jeans</em>.

So, 0.1x will represent how much of the original price Noah gets a a discount on.

Therefore, (x - 0.1x) represents the total cost of the jeans <em>after</em> the coupon.

So, x is our original price of the jeans.

Part 2)

To verify that 70 is <em>not</em> a solution, we can simply substitute 70 for x and check whether or not the equation is true. So:

(70)-0.1(70)+2.7\stackrel{?}{=}56.70

Multiply:

70-7+2.7\stackrel{?}{=}56.7

Subtract:

63+2.7\stackrel{?}{=}56.7

Add:

65.7\neq56.7

However, we <em>can</em> verify that 60 <em>is</em> the solution by substituting. So, substitute 60 for every x:

(60)-0.1(60)+2.7\stackrel{?}{=}5.7

Multiply:

60-6+2.7\stackrel{?}{=}56.7

Subtract:

54+2.7\stackrel{?}{=}56.7

Add:

56.7\stackrel{\checkmark}{=}56.7

So, 60 is indeed the solution and is the value of x.

So, this means that $60 was the original price of the jeans.

8 0
3 years ago
Read 2 more answers
What is 15% of 90? ..............​
mars1129 [50]

Answer:

13.5

hope it helpeddddd

:P

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
Guys i need ypur help pls help me​
Phoenix [80]

Answer:

D theBjquququaauauauaua0

5 0
3 years ago
Read 2 more answers
How do I work this out oof
kakasveta [241]

I am so sorry for giving you the wrong answer at first.

Here's the processs

1x=-0.5555

Move the decimal point in the repeating decimal one space forward

10x=-5.55555

Then subtract

10x=5.5555

x=-0.5555= 9x=-5

Divide both sides by 9

9x=-5

9x/9=-5/9

-5/9 is your final answer!

Hope this helps!

7 0
3 years ago
Read 2 more answers
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