Do "42 + 12" Since 7 x 6 is 42 and 4 x 3 is 12.
<span>since sin and cos = each other at pi/4; take your integrals from 0 to pi/4
</span><span>[S] cos(t) dt - [S] sin(t) dt ;[0,pi/4]
</span>
<span>to revolve it around the x axis;
we do a sum of areas
[S] 2pi [f(x)]^2 dx
</span>
<span>take the cos first and subtract out the sin next; like cutting a hole out of a donuts.
</span><span>pi [S] cos(x)^2 dx - [S] sin(x)^2 dx ; [0,pi/4]
</span>
<span>cos(2t) = 2cos^2 - 1
cos^2 = (1+cos(2t))/2
</span>
<span>1/sqrt(2) - (-1/sqrt(2) +1)
1/sqrt(2) + 1/sqrt(2) -1
(2sqrt(2) - sqrt(2))/sqrt(2) = sqrt(2)/sqrt(2) = 1</span>
Whole numbers, integers, rational numbers, natural numbers, real numbers
All of those are correct
Step-by-step explanation:
6x + 2 = y --------1
3y - 18x = 12 -----2
From 1
substitute y = 6x +2 in equation 2
3(6x + 2) - 18x = 12
18x + 6 - 18x = 12
Therefore, no solution!
