Answer:
1931.7N
Step-by-step explanation:
We are told in the question that :
An auto ( a car) weighs = 2500 pounds
It s inclined at n horizontal Ange of 10°
We are asked to find the force that would prevents it from rolling down the street.
Since the unit for Force = Newton or kgm/s²
Step 1
Convert Weight in pounds to kg
1 pound = 0.453592kg
2500 pounds =
2500 pounds × 0.453592kg
= 1133.981kg
Step 2
Find the force that would prevents it from rolling down the street.
Force = Mass × Acceleration due to gravity × sin θ
Acceleration due to gravity = 9.81m/s
Force = 1133.981kg × 9.81 × sin 10°
Force = 1931.7237321 N
Approximately = 1931.7N
Answer:
-7π/3 or -420 degrees
Step-by-step explanation:
So we know that the arrow has made one full rotation and that it is moving in a clockwise direction. So already we have -2π degrees.
The arrow stops at π/6 before the next π/2 rotation. Therefore we find the difference between the two.
π/2 - π/6
3π/6 - π/6 = 2π/6
π/3
Since this is still clockwise, we make this negative. So the measure of the angle shown by the arrow is -2π - π/3
Answer:
No solution
Step-by-step explanation:
3x + 6y =36
-3x - 6y =0
------------------add
0 ≠ 36
No solution
Answer:
-19
Step-by-step explanation:
you first substract 7 from 83 since its the inverse operation
then you divide it by -4 which give you -19
