Question

A common resistance of carbon resistors is 33 ΩΩ. How many 33 ΩΩ resistor, connected in parallel, are needed to give a total resistance of 5.5 ΩΩ?

Answer 1

Let n be the required number of 33 ohm resistors.
$n\times(\frac{1}{33})=\frac{1}{5.}$
$n=\frac{33}{5.5}=6$
The required number of 33 ohm resistors in parallel is 6 resistors.

Answer 2

Answer:

6 resistors.

Step-by-step explanation:

Common resistance of carbon resistors has been given as 3 Ω

When resistors added in parallel connection total resistance is given by the expression

$\frac{1}{R}$ = $\frac{1}{R_1}$ + $\frac{1}{R_2}$...........$\frac{1}{R_n}$

If n resistors have been added then $\frac{1}{R}$ = $\frac{n}{r}$

here r = 3Ω and R = (0.5)Ω

$\frac{n}{3}$= $\frac{1}{0.5}$

n = $\frac{3}{0.5}$ =  6 resistors.