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kolezko [41]
3 years ago
13

Consider the expression 103 x 0.006. a) What is the exponent in the power of 10? [ Select ] b) How many factors of 10 are in 103

? [ Select ] c) How do your answers to the last two questions relate to one another? [ Select ] d) What is the value of 103 x 0.006? [ Select ]
Mathematics
1 answer:
Katena32 [7]3 years ago
3 0

Solution :

Given that the expression is :

$10^3 \times 0.006$

This can be written as,

$\Rightarrow 10^3 \times \frac{6}{1000}$

$\Rightarrow 10^3 \times \frac{6}{10^3}$

$\Rightarrow 10^0 \times 6$

a). Therefore the exponent in the power of 10

     = 0

b). Factors of 10 in $10^3$

    = 10 x 10 x 10

    = 1000

    = $10^3$

   So there are 3 factors of 10 in $10^3$

c). If we compare the exponent of power of 10 in 1000 and factors of 10 in 1000, then both of them will be same.

  But in part a), we are finding exponent in the power of 10 in the expression  which is equal to 0. And in part b), we are finding the factor of 10 in 1000, which is equal to 3, as 10 x 10 x 10 = 1000.

d). The value of the expression $10^3 \times 0.006$ is 6.

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Step-by-step explanation:

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\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

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2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}

=2\cdot \:2\cdot \:2

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8

=8

=\frac{8\cdot \:27}{8\cdot \:125}

\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

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