Question

Write the log equation as an exponential equation

Answer 1

Answer:

$\displaystyle {9}^{2x - 1} = 2$

Step-by-step explanation:

we are given a logarithmic equation

$\displaystyle \log_{9}(2) = 2x - 1$

we want to rewrite it as exponential equation

remember that,

$\displaystyle\log_{a}(b) = c \iff {a}^{c} = b$

here our a is 9,b is 2 and c is 2x-1

altogether

our exponential equation is

$\displaystyle {9}^{2x - 1} = 2$

and we're done!