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Levart [38]
3 years ago
13

The value of y varies directly as the square of x and y=27 when x=9. Find the equation represents this relationship. Report the

proportionality constant as a reduced fraction when necessary.
Mathematics
1 answer:
skad [1K]3 years ago
8 0

Answer:

The relation between x and y is

y=\frac13 x^2

Step-by-step explanation:

Given that,

The value of y varies directly as the square of x.

y\propto x^2

\Rightarrow y=rx^2

where r is constant of proportional.

Given that,

y= 27 and x=9

Plug y= 27 and x=9 in above relation

y=rx^2

\therefore 27=r(9)^2

\Rightarrow 27 = r.81

\Rightarrow r=\frac{27}{81}

\Rightarrow r=\frac{1}{3}

The relation between x and y is

y=\frac13 x^2

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m∠RPQ = 8°

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m∠QRS is exterior angle and m∠RPQ and m∠PQr are opposite interior angles to m∠QRS

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4x - 15 = x +1 + x - 2

4x - 15 = x + x + 1-2          {Combine like terms}

4x - 15 = 2x - 1        {Subtract 2x from both sides}

4x - 2x - 15 = - 1

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x = 14/2

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