The width of the square is 7 cm. This is also the diameter of the circle.
To find the area of the square, you do 7², which is 49 cm².
To find the area of a circle, you do πr².
The radius is half the diameter, so it's 7 ÷ 2, which is 3.5 cm.
π3.5² ≈ 38.4845100065 cm².
The shaded region is the area of the square minus the area of the circle.
49 - 38.4845100065 = <span>10.5154899935, but because you're using 3.14 to approximate pi, the closest answer is 10.54 cm</span>².
The answer is 10.54 cm².
The answer to this would be complementary angles.
I believe that the answer is C.
Answers:
area = 50.24 square yards
circumference = 25.12 yards
values are approximate
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Work Shown:
d = 8 is the diameter
r = 4 is the radius, half the diameter
pi = 3.14 approximately
C = 2*pi*r = circumference
C = 2*3.14*4
C = 25.12 yards is the circumference. The circumference is the distance around the circle, aka the perimeter
An alternative formula you can use is C = pi*d
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A = area of circle
A = pi*r^2
A = 3.14*4^2
A = 50.24 square yards is the area
Answer:
the first problem is - 85 and you continue from there
We have the price of a senior ticket is $4 and the price of a child ticket is $7
Step-by-step explanation:
We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.
We have from day 1:
A: 3s + 9c = 75
And from day 2:
B: 8s + 5c = 67
Now we can rewrite A as:
A: 24s + 72c = 600
And can rewrite B as:
B: 24s + 15c = 201
Now A-B can be written as:
A-B: 57c = 399
So c = 7
Now substituting this back into A we get:
A: 3s + 63 = 75
A: 3s = 12
So s = 4
We have the price of a senior ticket is $4 and the price of a child ticket is $7
