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3 years ago

How do you solve 2x-2y+5=0 for x and then also for y

2 answers:

3 0

Solving for 'y'

2x - 2y + 5 = 0

Add 2y on both sides

2x + 5 = 2y

Divide by 2 on both sides

y = x + 5/2
y = x + 2.5

Solving for 'x'

2x - 2y + 5 = 0

Subtract 2x on both sides.

-2y + 5 = -2x

Divide 2x on both sides

x = y - 5/2
x = y - 2.5

Leokris [45]3 years ago

3 0

If you are trying to graph it, then you need to simplify it to simplest linear slope form: y = mx + b

As of now, you have 2x - 2y + 5 = 0

Isolate the y to one side of the equation, -2y = -2x - 5

Divide the entire equation by -2, to completely isolate the y,
y = x + 5/2

Basically, y = x + 5/2 and x = y - 5/2

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Prove that:- (1-sinA)(1+sinA)÷(1+cosA)(1-cosA)=cot^2A

astraxan [27]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 , then

sin²x = 1 - cos²x and cos²x = 1 - sin²x

Consider the left side

$\frac{(1-sinA)(1 + sinA)}{(1+cosA)(1-cosA)}$ ← expand numerator/denominator using FOIL

= $\frac{1-sin^2A}{1-cos^2A}$

= $\frac{1-(1-cos^2A)}{1-(1-sin^2A)}$

= $\frac{1-1+cos^2A}{1-1+sin^2A}$

= $\frac{cos^2A}{sin^2A}$

= cot²A = right side , thus proven

6 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

4 years ago

HELPPPP look at image

posledela

Your answer would be 24 and 168
take the 48 and divide by 4 to get the 1st one then just multiply 24 by 7 and you get 168

5 0

3 years ago

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If a watch cost 40 dollars and you must pay 6.5 sales tax how much will tax be

Serhud [2]

Answer:

$100

Step-by-step explanation:

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3 years ago

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Determine which cross products are proportionate to each other. Select all situations that apply.

Gemiola [76]

3/8y = 9/24 since 3*3=9 and 8*3=24
4 = 64/16 since 16*4=64
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4 years ago

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