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Montano1993 [528]

3 years ago

14

Examples of an interger that's not a whole number

1 answer:

rusak2 [61]3 years ago

6 0

-1, -5, -60, -123456 In general, those are negative integers.

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For vectors u= (3,4) and v= (1,3) find CompuV and the angle between u and v.

vampirchik [111]

Answer:

The angle between the given vectors u and v is $\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

Step-by-step explanation:

Given vectors are $\overrightarrow{u}=(3,4)$ and $\overrightarrow{v}=(1,3)$

Now compute the dot product of u and v:

$\overrightarrow{u}.\overrightarrow{v}=(3,4).(1,3)$

$=(3)(1)+(4)(3)$

$=3+12$

$=15$

Now find the magnitude of u and v:

$|\overrightarrow{u}|=\sqrt{3^2+4^2}$

$=\sqrt{9+16}$

$=\sqrt{25}$

$=5$

$|\overrightarrow{u}|=5$

$|\overrightarrow{v}|=\sqrt{1^2+3^2}$

$=\sqrt{1+9}$

$=\sqrt{10}$

$|\overrightarrow{v}|=\sqrt{10}$

To find the angle between the given vectors

$\overrightarrow{u}.\overrightarrow{v}=|\overrightarrow{u}|\overrightarrow{v}|cos\theta$

$\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]$

$=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]$

$=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]$

$\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

Therefore the angle between the vectors u and v is

$\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

3 0

3 years ago

Seven less than the product of twice a number is greater than 5 more than the same number. Which integer satisfies this inequali

melomori [17]

$2n-7>n+5 \\ 2n-7+7>n+5+7 \\ 2n>n+12 \\ 2n-n>n+12-n \\ n>12$

5 0

3 years ago

(b2) what's the missing exponent<br> = b−10

amid [387]

According to the given expression, the value of b if $b^2=b^{-10}\\$ is -1 and + 1

Indices are expressed using exponents and bases. Some of the useful laws of indices are:

$a^m\times a^n=a^{m+n}\\a^{-n}=\frac{1}{a^n}$

Given the expression;

$b^2=b^{-10}\\$

This can also be expressed as:

$b^2=\frac{1}{b^{10}}\\b^2 \times b^{10} =1\\b^{2+10} =1\\b^{12}=1\\b=\pm\sqrt[12]{1}\\b=\pm1$

Hence the value of b from the given indices is -1 and + 1

Learn more here: brainly.com/question/20298728

5 0

2 years ago

Is anyone really good at math?

Gre4nikov [31]

Answer: 12 cm

Step-by-step explanation:

$\mathtt{Using\ the \ pythagorean \ theorem: \\}$

$a^2+b^2=c^2, \\\ we\ can\ plug\ in\ values\ for\ a,\ b,\ and\ c$

$L=a\ and\ M=b\ and\ N=c$

Therefore,

$L^2+35^2=37^2\\L^2+1225=1369\\L^2=144\\\sqrt{L^2} =\sqrt{144} \\L=\pm12\\Taking\ only\ the\ positive\ answer,\ we\ get:\\\large\boxed{L = 12cm}$

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Roman has 415 baseball cards. He gives away

Sergio [31]

Answer:

45

Step-by-step explanation:

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3 years ago

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