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kozerog [31]
3 years ago
10

What is the solution to the system of equations? y=2/3x+3 x = –2

Mathematics
2 answers:
aliya0001 [1]3 years ago
6 0

Answer:

(-2, 5/3)

Step-by-step explanation:

Step 1: Write out systems of equations

y = 2/3x + 3

x = -2

Step 2: Substitution

y = 2/3(-2) + 3

y = -4/3 + 3

y = 5/3

Step 3: Write solution

(-2, 5/3)

mel-nik [20]3 years ago
5 0

Answer:

\boxed{(-2, \frac{5}{3} )}

Step-by-step explanation:

y = 2/3x+3

x = -2

Plug x as -2 in the first equation.

y = 2/3(-2) + 3

Solve for y.

y = -4/3 + 3

y = -4/3 + 3/1

y = -4/3 + 9/3

y = 5/3

The value of x is given already as -2.

The value of y is 5/3.

The solution to the system of equations is (-2, 5/3).

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Answer:

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DE

= \sqrt{ {(3 - 5)}^{2} +  {(1 + 1}^{2}  }  \\   = \sqrt{ {( - 2)}^{2}  +  {(2)}^{2} }  \\    = \sqrt{4 + 4}  \\  =  \sqrt{8}  \\   = 2 \sqrt{2}

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

<u>scale factor</u> = AB/DE

= 2

It's been reflected across the Y-axis

<em>moved thru the translation of 3 units towards the right of positive x- axis </em>

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7 0
2 years ago
Solve each equation. Show your work<br><br> 13a=-5<br> 12−b=12.5<br> -0.1=-10c
amid [387]
1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385

The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
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(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)

-b/-1= 0.5/-1
Therefore b=-0.5

The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10

Hence, c= 0.01
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topjm [15]

Answer:

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Step-by-step explanation:

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