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pishuonlain [190]
3 years ago
5

When the puppy turned 12 months old it weighed 19.6

Mathematics
1 answer:
alina1380 [7]3 years ago
4 0

Answer:

#&*#*#

Step-by-step explanation:

what typa dog is it???

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To investigate the relationship between age and preference for two mayoral candidates in an upcoming election, a random sample o
OLga [1]

Answer:

0.15401

Step-by-step explanation:

Given that test statistic = 3.7408

From the question, we could deduce that, this is scenario could be analysed A ONE - WAY analysis of Variance method as it has one independent variable, Age subdivided into 3 levels

The test statistic value obtained is the Chisquare (χ²) value, which equals 3.7408

To Obtain the requested Pvalue, we need the degree of freedom, which is :

(Number of columns - 1) * (number of rows - 1)

Number of candidates = 2

Number of levels = 3

Hence,

Degree of freedom = (3 - 1) * (2 - 1) = 2 * 1 = 2

Using the Chisquare Pvalue calculator or distribution table :

χ²;3.7408, 2 = 0.154062

Pvalue = 0.1541

3 0
3 years ago
Graph the system of equation below on a piece of paper what is the solution y=x-1 and y=-2x+5
ANTONII [103]

We are given

First equation:

y=x-1

we can use formula

y=mx+b

slope is m=1

y-intercept is b=-1

Second equation:

y=-2x+5

we can use formula

y=mx+b

slope is m=-2

y-intercept is b=5

Graph:

We can see that

both curves intersect at (2,1)

so, solution is x=2 and y=1.................Answer

6 0
3 years ago
ILL GIVE YOU BRAINLIEST PLEASE ANSWER
Gennadij [26K]

Answer:

376.9 ft²

Step-by-step explanation:

There you go the right answer

6 0
2 years ago
The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source
Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> (2-4\mathbf{i})\ V

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

2 + 6\mathbf{i}

a + b\mathbf{i}

2 - 5\mathbf{i}

The sum of these voltages is:

V_t=4+a+(6+b-5)\mathbf{i}

Operating:

V_t=4+a+(1+b)\mathbf{i}

We know the total voltage is 6-3\mathbf{i}, thus:

4+a+(1+b)\mathbf{i}=6-3\mathbf{i}

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is (2-4\mathbf{i})\ V

5 0
2 years ago
What is the solution to -2(8x – 4) &lt; 2x + 5?<br>він<br>x x<br>оооо<br>x x<br>заще<br>х: 6<br>о​
lozanna [386]

Answer:

The answer to the question is x<3/18

7 0
3 years ago
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