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3 years ago

When the puppy turned 12 months old it weighed 19.6

Mathematics

1 answer:

alina1380 [7]3 years ago

4 0

Answer:

#&*#*#

Step-by-step explanation:

what typa dog is it???

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(question in picture) please help me!!

Colt1911 [192]

Answer:

B is the correct answer hope this helps!

6 0

3 years ago

Solve each inequality analytically, writing the solution set in interval notation. Support your answer graphically. (Hint: Onc

Sidana [21]

Part (a)

$9-(x+4)$

Part (b)

$x \in (-\infty, 5]$

8 0

2 years ago

Drag each number to the correct location on the table. Each number can be used more than once, but not all numbers will be used.

muminat

Answer:

1. $12x^2-13.4x-11$

- Degree: 2

- Number of terms: 3

2. $7x^3+168$

- Degree: 3

- Number of terms: 2

3. $9x^4-9$

- Degree: 4

- Number of terms: 2

Step-by-step explanation:

For this exercise you need to remember the multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

1. Given:

$(4x + 2.2)(3x - 5)$

Apply the Distributive property:

$=12x^2+6.6x-20x-11$

Add the like terms:

$=12x^2-13.4x-11$

You can idenfity that:

- Degree: 2

- Number of terms: 3

2. Given:

$(-304 +503 - 12) + (7x^3 - 25 + 6)$

Add the like terms:

$=187 + 7x^3 - 25 + 6=7x^3+168$

You can idenfity that:

- Degree: 3

- Number of terms: 2

3. Given:

$(3x^2 - 3)(3x^2 + 3)$

Apply Distributive property:

$=9x^4-9x^2+9x^2-9$

Add the like terms:

$=9x^4-9$

You can idenfity that:

- Degree: 4

- Number of terms: 2

8 0

3 years ago

What is the volume of 2 G piece of gold? (Best answers gives brainlist answers)

Fed [463]

Answer:

2 grams

Step-by-step explanation:

2 grams of gold is equivalent to 2 grams

6 0

4 years ago

Two movie tickets and 3 snacks are $24. Three movies tickets and 4 snacks are $35. How much is a movie ticket and how much is a

Vsevolod [243]

Answer: A movie ticket is $9 while a snack is $2

Step-by-step explanation: We shall let a movie ticket be m while a snack is s. So, from the clues given, if two movie tickets and three snacks cost $24, we can write it as the following expression;

2m + 3s = 24

Also if three movie tickets and four snacks cost $35, we can as well write another expression as follows;

3m + 4s = 35.

Now we have a pair of simultaneous equations which are

2m + 3s = 24 ----------(1)

3m + 4s = 35 ----------(2)

We shall solve this by using the elimination method, since none of the variables has a coefficient of 1. We'll start by multiplying equation (1) by 3 and multiplying equation (2) by 2 (so as to eliminate the m variable)

2m + 3s = 24 -------- x3

3m + 4s = 35 ---------x2

We now arrive at the following

6m + 9s = 72--------(3)

6m + 8s = 70--------(4)

Subtract equation (4) from equation (3) and we arrive at

s = 2

Having determined that s equals 2 we can now substitute for the value of a into equation (1)

2m + 3s = 24

2m + 3(2) = 24

2m + 6 = 24

Subtract 6 from both sides of the equation

2m + 6 - 6 = 24 - 6

2m = 18

Divide both sides of the equation by 2

m= 9

Therefore one movie ticket costs $9 while one snack costs $2

6 0

4 years ago