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pishuonlain [190]
2 years ago
5

When the puppy turned 12 months old it weighed 19.6

Mathematics
1 answer:
alina1380 [7]2 years ago
4 0

Answer:

#&*#*#

Step-by-step explanation:

what typa dog is it???

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- 11 = a/6 need help with this ?
JulijaS [17]

a= -66

-11=a/6

-66=a

a=-66

hopes this helps,

Xeno


5 0
2 years ago
The surface areas of two similar solids are 169 m2 and 81 m2. the volume of the larger solid is 124.92 m3. which proportion corr
ikadub [295]

By finding the scale factor, we will see that the volume of the smaller solid is 86.75 m³.

<h3>How to get the volume of the smaller solid?</h3>

If the solids are similar, then there is a scale factor between the two. Then the relation between the areas is equal to the scale factor squared, and the relation between the volumes is equal to the scale factor cubed.

This means that if the areas are 169 m² and 81 m², then we can write:

169 m² = (k²)*81 m²

Solving for k, we get:

k = √(169 m²/81 m²) = 1.44

Then if the volume of the large solid is 124.92m³ we can write:

124.92m³ = k³*V

Replacing k and solving for V we get:

124.92m³ = (1.44)³*V

(124.92m³/ (1.44)³) = V = 86.75 m³

If you want to learn more about scale factors:

brainly.com/question/3457976

#SPJ4

6 0
2 years ago
Read 2 more answers
Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
3 years ago
Help pls!!
hodyreva [135]

Answer:

C) 33 meters

Step-by-step explanation:

In this question, we need to find the value of the variable "x".

To do this, we must use the Pythagorean theorem: a² + b² = c²

Plug in your values and solve:

56² + b² = 65²

3,136 + b² = 65²

3,136 + b² = 4,225

Subtract 3,136 from both sides.

b² = 1,089

To cancel out the exponent, we would square root both sides.

√b² = √1,089

b = 33

This means that C) 33 meters will be your answer.

3 0
2 years ago
Read 2 more answers
What is the solution of this linear system? x+y=13
igor_vitrenko [27]

Answer:

The solution of the linear equation is: (6,7)

Step-by-step explanation:

This being that:

x + y = 13

1/2x + y = 10

What you do in order to find the solution is either (2 ways):

- Substitution

- Elimination

I'm sure that either way, you'll get the same thing. I used: Substitution.

To do this choose either if you want to find [x] or [y] first, then substitute it in. I will choose to find [x] first.

<h2>x + y = 13</h2><h2><u>           - y </u>    </h2><h2>x = 13 - y</h2>

Now substitute it into:  

1/2x + y = 10

1/2(13 - y) + y = 10

1/2(13 -y) + y= 10

<h2>Then to get rid of fraction, instead of dividing, you multiply with reciprocal</h2><h2>1/2 · 2/1 (They cancel out) Leaving you with:</h2><h3 /><h3>(13 - y) 2(y) = 2(10)</h3><h3>(Everything is multiplied, except for 13 - y, because it had parenthesis to protect it.)</h3><h3>13 - y + 2y = 20</h3><h3 /><h2>13 + y = 20</h2><h2><u>- 13       - 13</u></h2><h2>           <u>y = 7</u></h2><h2 /><h2>You now have your [y] for your coordinate.</h2><h2>(x, 7), now time to find your [x]</h2><h2 />

Now you substitute your [y] into your equation:

1/2x + (7) = 10

<h2>1/2x + 7 = 10</h2><h2><u>          -7 = -7</u></h2><h2>1/2x = 3</h2><h2>(To get rid of fraction, multiply on both sides with reciprocal)</h2><h2>1/2 cancels out with 2/1</h2><h2>x = 2(3)</h2><h2>x = 6</h2><h2>You now have your [x] coordinate.</h2><h2 /><h2>This is your coordinate: </h2><h2>(6,7)</h2><h2></h2>

 

4 0
3 years ago
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