Answer:
The center is (-10,10) and the radius is 4sqrt(3)
Step-by-step explanation:
(x + 10)^2 + (y - 10)^2 = 48
We can write the equation of a circle as
(x -h)^2 + (y - k)^2 = r^2 where (h,k) is the center and r is the radius
(x- -10)^2 + (y - 10)^2 = (sqrt(16*3) )^2
(x- -10)^2 + (y - 10)^2 = (4sqrt(3)) ^2
The center is (-10,10) and the radius is 4sqrt(3)
Answer:
02 High Schools would be selected from the stratum with a percent-free-lunch value of 40 less than or equals x.
Step-by-step explanation:
As the sample size needed is 25 and total schools are 100 so this indicate 1 school in each 4 schools is to be selected. This is given as
Now as the schools with percent free lunch are 8 so now
So only 2 schools will be selected in this regard.
1)
I:x-y=-7
II:x+y=7
add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0
insert x=0 into II:
0+y=7
y=7
the solution is (0,7)
2)
I: 3x+y=4
II: 2x+y=5
add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1
insert x=-1 into I:
3*-1+y=4
y=7
the solution is (-1,7)
3)
I: 2e-3f=-9
II: e+3f=18
add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3
insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5
the solution is (3,5)
4)
I: 3d-e=7
II: d+e=5
add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3
insert d=3 into II:
3+e=5
e=2
the solution is (3,2)
5)
I: 8x+y=14
II: 3x+y=4
add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2
insert x=2 into II:
3*2+y=4
y=4-6
y=-2
the solution is (2,-2)
Volume of the Rectangular prism is 2340 square units
Step-by-step explanation:
Given:
X = 13 units,
Y = 12 units,
Z = 15
To Find:
The volume of the rectangular prism = ?
Solution:
The volume of the rectangular prism = 
On substituting the values,
Volume of the Rectangular prism =
Volume of the Rectangular prism = 2340 square units
