You want to write this equation in the form (x+...)(x+...) (maybe with a minus sign). To do this, find numbers that, when multiplied, give 16, and when added give -10.
What whole numbers give 16?
1*16 and -1*-16
2*8 and -2*-8
4*4 and -4*-4
Which of these solutions, when changed into a sum, give -10?
Try them one by one and find it is:
-2-8 = -10.
So (x-2)(x-8) is the factorization!
This is really a bit of trial and error, but since most of the time the assignments deals with whole numbers, there aren't that many possibilities.
Answer:
y=1/2x-4
Step-by-step explanation:
2y-x=-8
2y=x-8
y=1/2x-4
Answer:
c.
Step-by-step explanation:
It's c because as x increases so does y and when x = 0, y = 3(3)^0
= 3*1 = 3.
X=475
Subtract $600 form both sides
$600-$125=$475 | $600-$600=$0
$475+$125=$475