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storchak [24]
3 years ago
9

2+2=3+1 what's the answer for this problem

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0
4=4, it would be correct
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In a right triangle, the hypotenuse is three inches more than twice the length of one leg. If the other leg is 12 inches, what i
andrew-mc [135]

Answer:

Length of hypothenuse = 13 inches

Length of other leg = 5 inches

Step-by-step explanation:

A triangle has three sides and three angles. A right angle triangle has 90 degrees as one of the angles. The remaining two angles are complimentary. This means that the sum if the other two angles is 90 degrees.

The longest side is the hypotenuse. The shorter sides are the opposite and adjacent.

In this triangle, the hypotenuse is three inches more than twice the length of one leg. Let the length of one leg be x inches.

Hypothenuse = 2x + 3

The other leg is 12 inches.

The diagram is illustrated in the attached photo.

Applying Pythagoras theorem,

Hypothenuse ^2 = adjacent^2 + opposite ^2

(2x+3)^2 = 12^2 + x^2

(2x+3)(2x+3)= 144 + x^2

4x^2 + 6x + 6x + 9 = 144 + x^2

4x^2 - x^2 + 6x + 6x + 9 - 144 = 0

3x^2 +12x - 135 = 0

3x^2 +27x - 15x - 135 = 0

3x(x+9)-15(x+9)=0

(3x -15)(x+9) = 0

3x -15 = 0 or x+9= 0

3x = 15 or x = -9

x = 15/3 = 5

x = 5inches because it cannot be negative.

Length of hypothenuse = 2x + 3

= 2×5 + 3 = 10 + 3 = 13 inches

6 0
3 years ago
P pennies added to 22 pennies
taurus [48]
23 Pennie’s is the answer I believe
7 0
2 years ago
Select all the correct answers.
11Alexandr11 [23.1K]

Statement 3 and 4 are true as Figures 1 and 2 are not congruent and Figures 1 and 3 are not congruent

<h3>What are Congruent Figures ?</h3>

The figures that are similar in shape and size or can be mapped into one another , such figures are called Congruent Figures.

The graph has been plotted on the basis of given data.

The plot can be seen in the graph attached with the answer.

The statements that are true according to the given data is

Statement 3 and 4 are true as

Figures 1 and 2 are not congruent because figure 1 cannot be mapped onto figure 2 using a sequence of rigid transformations.

Figures 1 and 3 are not congruent because figure 1 cannot be mapped onto figure 3 using a sequence of rigid transformations.

To know more about Congruent Figures

brainly.com/question/12132062

#SPJ1

4 0
2 years ago
What is the measure of angle A?
fgiga [73]

Answer:

∠A=65º

Step-by-step explanation:

  • A angle of a line is 180º, so we can say that angle ABC=(180-6x)º
  • The interior angkes of a triangle is 180º, so (x+40)º+(3x+10)º+(180-6x)º=180º
  • Remove parenthesis, x+40+3x+10+180-6x=180
  • Combine like terms, -2x+230=180
  • Subtract 180, -2x=-50
  • Divide by -2, so x=25

Now:

  • ∠CAB=(25+40)º=65º
  • ∠ABC=[180-6(25)]º=30º
  • ∠BCA=[3(25)+10]=85º
5 0
3 years ago
What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

=a^2\text{ square cm}

Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

4 0
3 years ago
Read 2 more answers
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