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Anon25 [30]
2 years ago
10

Phill thinks he had merited the angles blew correctly. Triangle placed on top of a straight line, 50 * at the top left of the tr

iangle, 90 at the bottom left of the triangle, 40* at the bottom right

Mathematics
1 answer:
Vikki [24]2 years ago
8 0
No he is wrong because if it were 150° on the right side it would be 30° on the other side
You might be interested in
The number of marriage licenses issued by Clark County Nevada, the county where Las Vegas is located, has been
REY [17]

The number of marriage licenses were issued in 2003 is 21586.

According to the statement

we have to find the number of marriage licenses were issued in 2003

and the given equation is y=3.405x^2-17674x+21533000

And in this equation x represent the time

And Y represent the number of marriage certificate issued.

So, in given equation

y=3.405x^2-17674x+21533000

we fill the value of X and find the value of Y means tne number of marriage license is issued in 2003

We know that X = 3 from 2000 to 2003

Then put X=3 in the given equation.

Then

This is the equation (1) represent the change

y=3.405(3)^2-17674(3)+21533000 -(1)

y = 30.645+53022+21533000

y = 21586052.645

On nearest hundred the value becomes 21586.

So, The number of marriage licenses were issued in 2003 is 21586.

Learn more about NUMBERS here brainly.com/question/1770447

DISCLAIMER: The question was incomplete. please find the full content below.

QUESTION:

According to the model, how many marriage licenses were issued in 2003? Round your answer to the nearest hundred.

The number of marriage licenses issued by Clark county Nevada, the county where Las Vegas is located, has been decreasing since the year 2000. This can be modeled by y=3.405x^2-17674x+21533000 where x is the year and y is the number of marriage licenses issued.

#SPJ1

5 0
1 year ago
A community college has 2,000 students and 50 instructors. Next year the enrollment will be 6,000. How many new instructors shou
juin [17]
\begin{array}{ccc}2,000&-&50\\\\6,000&-&x\end{array}\\\\\\2,000x=50\times6,000\ \ \ \ \ /:2,000\\\\x=\frac{300,000}{2,000}\\\\x=150\\\\150-50=100\\\\Answer:100\ new\ instructors.
7 0
3 years ago
Find the area of the following shapes:
Annette [7]

Answer:

24 square units

Step-by-step explanation:

You apply area of a trapezium

5 0
2 years ago
A computer programming team has 17 members. (a) How many ways can a group of nine be chosen to work on a project? As in Example
Natali5045456 [20]

The number of groups that can be chosen from the team of 17 depends on the given conditions of the selection.

The correct responses are;

(a) The number of ways of choosing groups of 9 from the 17 members are 24,310 ways.

(b) (i) The number of groups of 9 containing 5 women and 4 men are 8,820 groups.

(ii) The number of groups of 9 that contain at least one man is 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) If two team members refuse to work together on projects, the number of groups of 9 that can be chosen are 17,875 groups.

(d) If two team members must work together or not at all the number of groups of 9 that can be chosen are 1,430 groups.

Given,

The combination of n objects taking r at a time is given as follows

ₙCr = (ⁿr)

(a) The number of ways of choosing groups of 9 from the 17 members is given as follows;

Number of ways of choosing groups of 9 = (17, 9)  = 24,310 ways.

(b) (i) Number of women = 9

Number of men = 8

Number of groups of 9 containing 5 women and 4 men = (9, 5) x (8, 4)

(9, 5) x (8, 4) = 126 x 70 = 8820

Number of groups of 9 containing 5 women and 4 men = 8,820 groups.

(ii) The number of groups that contain at least one man is (17, 9) - (9, 9)

(17, 9) - (9, 9) = 24,310 - 1 = 24,309

The number of groups that contain at least one man are 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women if given as follows;

(8, 8) × (9, 1) + (8, 7) × (9, 2) + (8, 6) × (9, 3) = 2649

The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) Given that two team members refuse to work together on projects, the number of groups of 9 that can be chosen are (15, 9) + 2 × (15, 8)

(15, 9) + 2 × (15, 8) = 5,005 + 2 × 6,435 = 17,875

(d) Two team members must work together or not at all is (15, 7) - (15, 9)

(15, 7) - (15, 9) = 6,435 - 5,005 = 1,430

The number of groups of 9 that can be chosen two team members must work together or not at all are 1,430 groups.

Learn more about number of ways here;

brainly.com/question/25310371

#SPJ4

7 0
1 year ago
Anya recorded the height in inches of 10 students in her class. The results are shown below.
Juliette [100K]
D, add all your answers than divide by how many numbers there are
8 0
2 years ago
Read 2 more answers
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