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Anna11 [10]
4 years ago
6

What is the correct name for the angle shown

Mathematics
1 answer:
Vesna [10]4 years ago
4 0

Answer:

i dont see no angle

Step-by-step explanation:

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How do I work this out I need full answer im lost​
taurus [48]

Answer:

7x = 35cm ; 2x = 10cm

Step-by-step explanation:

7x and 2x are the lengths

7x+2x=45

Then you take 7 + 2 = 9

so is gonna be 9x = 45

then you divide both side with 9

so is gonna be x = 5

Then you take 5 multiply 7 : 2

so 7 x 5 = 35cm

2 x 5 = 10cm

7 0
3 years ago
Write an equation of the line passing through point P(0,-1) that is parallel to the line y=-2x+3
irinina [24]

The answer to this question is:

y = -2x - 1

8 0
4 years ago
1
MrRa [10]

Answer:

2,995 or 35,940(?)

Step-by-step explanation:

I don't exactly remember how to do this so, I'll show you two different ways I solved this

Use the formula I=P*r*t

I=Interest

P=Principal

r=rate

t=time

To solve this you'll have to...

The principal is 29,950, the rate is 5% but it'll become a decimal which is 0.05, and the time is 2

Put it into the formula form 29,950*0.05*2= 2,995 in interest

Or...

You'll use the same formula, but this time multiply 0.05 by 12 since there are 12 months in one year which is 0.6, so...

29,950*0.6*2=35,940 in interest

I hope one works!

4 0
3 years ago
The amoebas on a petri dish is doubling every 5 minutes. If there are currently 8 amoebas on the dish, how many will there be in
pychu [463]

Answer:

32,768.

Step-by-step explanation:

There are 12 lots of 5 minutes in 1 hour.

The equation  is 8*(2^12)

= 8 * 4096

= 32,768.

3 0
3 years ago
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:
Vikentia [17]

Answer:

a

   \= x  = 18.5  ,  \sigma =  5.15

b

 15.505 < \mu <  21.495

c

 14.93 < \mu <  22.069

Step-by-step explanation:

From the question we are are told that

    The  sample data is  21, 14, 13, 24, 17, 22, 25, 12

     The sample size is  n  = 8

Generally the ample mean is evaluated as

        \= x  =  \frac{\sum x  }{n}

        \= x  =  \frac{  21 + 14 + 13 + 24 + 17 + 22+ 25 + 12  }{8}

         \= x  = 18.5

Generally the standard deviation is mathematically evaluated as

         \sigma =  \sqrt{\frac{\sum (x- \=x )^2}{n}}

\sigma =  \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}

\sigma =  5.15

considering part b

Given that the confidence level is  90% then the significance level is evaluated as

         \alpha  =  100-90

         \alpha  = 10\%

         \alpha  = 0.10

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.645

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.645  *  \frac{5.15 }{\sqrt{8} }

=>     E =  2.995

The 90% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 -  2.995 < \mu <  18.5 +  2.995

       15.505 < \mu <  21.495

considering part c

Given that the confidence level is  95% then the significance level is evaluated as

         \alpha  =  100-95

         \alpha  = 5\%

         \alpha  = 0.05

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.96

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.96  *  \frac{5.15 }{\sqrt{8} }

=>     E = 3.569

The 95% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 - 3.569 < \mu <  18.5 +  3.569

       14.93 < \mu <  22.069

8 0
3 years ago
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