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guajiro [1.7K]
3 years ago
7

Michael bought a new car. The sticker price was $6,100. He decided not to buy a warranty or any upgrades to the car. However, he

ended up paying much more. Why?
Mathematics
2 answers:
marin [14]3 years ago
5 0
I believe it is due to sales tax. Hope this helps!
kozerog [31]3 years ago
4 0

I believe it is due to sales tax.


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What is the solution of 9+ 1/4 = 7
Vlada [557]

Answer:

b=-8

Step-by-step explanation:

9+1/4b=7

-2=1/4b

b=-8

6 0
2 years ago
Read 2 more answers
By rounding each number to 1sf estimate the answers to 8.2*6.7/ 0.46
LiRa [457]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

8.2\times \frac{6.7}{0.46}

\mathrm{Multiply\:fractions}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c}

=\frac{6.7\times \:8.2}{0.46}

\mathrm{Multiply\:the\:numbers:}\:6.7\times \:8.2=54.94

=\frac{54.94}{0.46}

=100        (Round to 1 significant number)

8 0
3 years ago
Read 2 more answers
Need help ASAP thanks
Otrada [13]

Answer:

area of sector= teete ×πr²

360

<u>4</u><u>0</u><u>°</u>×<u>2</u><u>2</u>×2×2

360 7

<u>4</u><u>0</u><u>×</u><u>8</u><u>8</u>

2520

<u>3</u><u>5</u><u>2</u><u>0</u>

2520

=1.397°

7 0
2 years ago
The temperature in a town is 37.5°F during the day and -7.6°F at night. Find the difference in the temperatures
Masteriza [31]

Answer: The answer would be 18.1

Step-by-step explanation:

10.5 minus -7.6 = 18.1

To check your work do -

18.1 + -7.6 = 10.5

5 0
2 years ago
The mean per capita income is 23,037 dollars per annum with a variance of 149,769. What is the probability that the sample mean
mihalych1998 [28]

Answer:

Probability that the sample mean would be less than 23,013 dollars is 0.2358.

Step-by-step explanation:

We are given that the mean per capita income is 23,037 dollars per annum with a variance of 149,769.

Also, a sample of 134 persons is randomly selected.

Firstly, Let \bar X = sample mean

The z-score probability distribution for sample mean is given by;

              Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean per capita income = 23,037 dollars p.a.

           \sigma = standard deviation = \sqrt{Variance} = \sqrt{149,769} = 387 dollars p.a

           n = sample of persons = 134

So, probability that the sample mean would be less than 23,013 dollars is given by = P(\bar X < 23,013 dollars)

      P(\bar X < 23,013) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{23,013-23,037}{\frac{387}{\sqrt{134} } } ) = P(Z < -0.72) = 1 - P(Z \leq 0.72)

                                                                    = 1 - 0.7642 = 0.2358

The above probability is calculated using the z-score table.

<em>Therefore, probability that the sample mean would be less than 23013 dollars if a sample of 134 persons is randomly selected is 0.2358.</em>

4 0
2 years ago
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