The shape with the most area with the smallest perimiter is the circle
first find the radius
then find the circumfernece(permiter)
so
area=64
shape=circle
area of circle=pi times r^2
pi times r^2=64
divide both sides by pi (aprox 3.141592)
r^2=20.3718
square root both sdies
r=4.5
circumference=2pi times r
2 times 3.141592 times 4.5=28.36
perimiter is 28.36
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
Step-by-step explanation:
Step 1: Given equation: 
To get u, by subtraction equality property subtract both sides of the equation by 
.
Step 2: By division equality property, divide both sides of the equation by t.
Therefore, 
.
So, in Emily’s physics class, she got .
The slope is 2 and the y intercept is 3 m = 3 and b = 2x
This is invisible math but a whole bumber cant be converted to a decimal because if you were to see the whoole thing it would be 400.0
