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2 years ago

9

In September a clothing store had a sale where you could get 5 scarves for $28.35. In October the price was changed to 7 scarves

for $40.39. In which month did a scarf cost the most?

1 answer:

kykrilka [37]2 years ago

7 0

Answer: october

Step-by-step explanation:

for october its 5.77

and for september its 5.67

so october is the answer

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3 years ago

The price of a watch was increased by 10% to £132. What was the price before the increase?

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Answer:120

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2 years ago

Read 2 more answers

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

bija089 [108]

<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

<em>________________________________</em>

Hope it helps!! (:

4 0

2 years ago

A cement walk 3 ft wide is placed around the outside of a rectangular garden plot that is 20ft by 30ft. Find the cost of the wal

Inessa05 [86]

Let us calculate the area of the walk.

Since the width of the walk is 3 feet, and the walk will be placed all the 4 sides,

Length of the plot including walk = 20 + (2 × 3) = 20 + 6 = 26 feet.

Breadth of the plot including walk = 30 + (2 × 3) = 36 feet.

Area of the plot including walk = 26 × 36 square feet.

Area of the plot = 20 × 30 square feet.

Area of the walk = (26 × 36) - (20 × 30)

= 936 - 600

= 336 square feet.

= $\frac{336}{3(3)}$ square yards

= 37.3 square yards

Cost of the walk per square yard = $12.25.

Therefore, total cost of the walk = 12.25 × 37.3 = $456.92.

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2 years ago