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2 years ago

9

In September a clothing store had a sale where you could get 5 scarves for $28.35. In October the price was changed to 7 scarves

for $40.39. In which month did a scarf cost the most?

1 answer:

kykrilka [37]2 years ago

7 0

Answer: october

Step-by-step explanation:

for october its 5.77

and for september its 5.67

so october is the answer

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Julie made $22,$55,38,25 how much did she made ?

Dennis_Churaev [7]

Are you trying to add together everything she made in a span of time? If so:
22 + 55 + 38 + 25 = 140

7 0

3 years ago

A spool contains 270 inches of wire. How many pieces of wire, each with the a length of 1 7/8 inches, can be cut from the spool?

prisoha [69]

You would be able to cut 144 pieces of wire from the spool because 270/1 7/8 (or 1.875) equals 144

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3 years ago

Plz help, answer the question below

Afina-wow [57]

$\sqrt[6]{x^{16}} =\sqrt[6]{x^{12} \cdot x^{4}}=x^2\sqrt[6]{x^{4}}$

5 0

3 years ago

A line of best fit predicts that when x equals 28, y will equal 27.255, but y actually equals 26. What is the residual in this c

zlopas [31]

Answer:

C) -1.255

Step-by-step explanation:

We are tasked to solve for the residual value given that when x equals 29, y will be equals to 27.255. But, when it is tested, y actual value is 26. The formula in solving residual is shown below:

Residual value = Observed value - predicted value

Residual value = 26 - 27.255

Residual values = -1.255

The answer is -1.255 for residual value.

5 0

2 years ago

The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista

baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{10.634 - \mu}{\sigma}$

$10.634 - \mu = 1.28\sigma$

$\mu = 10.634 - 1.28\sigma$

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{9.7565 - \mu}{\sigma}$

$9.7565 - \mu = -1.96\sigma$

$\mu = 9.7565 + 1.96\sigma$

We also have that:

$\mu = 10.634 - 1.28\sigma$

So

$10.634 - 1.28\sigma = 9.7565 + 1.96\sigma$

$1.96\sigma + 1.28\sigma = 10.645 - 9.7565$

$3.24\sigma = 0.8885$

$\sigma = \frac{0.8885}{3.24}$

$\sigma = 0.2742$

The mean is

$\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65$

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0

3 years ago