0.27=_ hundredthsplease help me

Mathematics

2 answers:

Cloud [144]3 years ago

5 0

Answer:

Step-by-step explanation:

First decimal is tenths, then hundredths, then thousandths and so on

Alexeev081 [22]3 years ago

4 0

Answer:

27 hundredths

Step-by-step explanation:

.2 is in the tenths place,

.07 is in the hundredth place,

.27 is 27 hundredths

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Geometry help me please

11Alexandr11 [23.1K]

The first blank is segment addition postulate and the second blank is substitution property of equality

5 0

3 years ago

Either enter an exact answer in terms of .. or use 3.14 for .. and round your final answer to the nearest hundredth

expeople1 [14]

Answer:

981.25 units 3

Step-by-step explanation:

(area of slide triangle * area of bottom circle)

((5*5)/2)*(3.14*5*5) = 981.25 units 3

4 0

3 years ago

Calculate: ㅤ <img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Crightarrow%20%2B%5Cinfty%7Dx%28%5Csqrt%7Bx%5E%7B2%7D-1%7D-x%29"

RSB [31]

Answer:

$\displaystyle \large \boxed{ \lim_{x \rightarrow +\infty} {x\left(\sqrt{x^2-1}-x\right)}=-\dfrac{1}{2}}$

Step-by-step explanation:

Hello, please consider the following.

$\sqrt{(x^2-1)}-x\\\\=\sqrt{x^2(1-\dfrac{1}{x^2})}-x\\\\=x\left( \sqrt{1-\frac{1}{x^2}}-1\right)$

For x close to 0, we can write

$\sqrt{1+x}=1+\dfrac{1}{2}x-\dfrac{1}{8}x^2+o(x^2)\\\\\ \text{x tends to } +\infty \text{ means }\dfrac{1}{x} \text{ tends to 0}\\\\\text{So, when }\dfrac{1}{x}\text{ is close to 0, we can write.}\\\\\sqrt{1-\dfrac{1}{x^2}}=1-\dfrac{1}{2}\dfrac{1}{x^2}-\dfrac{1}{8}\dfrac{1}{x^4}+o(\dfrac{1}{x^4})$