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Lena [83]
2 years ago
9

SOLVE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
siniylev [52]2 years ago
4 0

Answer:

The answer is b= 0

Step-by-step explanation:

Hope this helped you

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Number 1 has a picture
MA_775_DIABLO [31]
Question 1

cos(C) = adj/hyp
cos(C) = BC/AC
cos(C) = 15/17

Answer: Choice C) 15/17

=============================================

Question 2

sin(E) = opp/hyp
sin(E) = FD/DE
sin(E) = 24/25

So angle E is the answer

=============================================

Question 3

AC is the adjacent side to the given angle A = 33 degrees
AB = 14 is the hypotenuse

cos(angle) = adjacent/hypotenuse
cos(33) = x/14
14*cos(33) = x
x = 14*cos(33)
x = 11.741
x = 11.7

Answer: 11.7

=============================================

Question 4

x = length of board

cos(angle) = adj/hyp
cos(55) = 6/x
x*cos(55) = 6
x = 6/cos(55)
x = 10.46068
x = 10.5

Answer: 10.5

=============================================

Question 5

112 is the adjacent side to the given angle 62 degrees
x = height of building, which is the opposite leg

tan(angle) = opp/adj
tan(62) = x/112
112*tan(62) = x
x = 112*tan(62)
x = 210.641364
x = 210.6

Answer: 210.6
3 0
3 years ago
Jean cost $45, they are now priced $40. find the percent of change from $45 to $40
Kisachek [45]
The percent of change is 9%
3 0
3 years ago
Help with special right triangle please
Ahat [919]

Answer:

Step-by-step explanation:

Looking at the right angle triangle that contains x and y, we would apply trigonometric ratio to determine x an y. Taking 60 degrees as the reference angle,

Hypotenuse = y

Adjacent side = x

Opposite side = 36

Therefore,

Sin # = opposite side / hypotenuse

Sin 60 = 36/y

y = 36/Sin60 = 36/0.8660 = 41.57

Cos # = adjacent side/hypotenuse

Cos 60 = x/41.57

x = 41.57Cos 60 = 41.57 × 0.5 = 20.785

Sin45 = z/36

z = 36Sin45 = 36 × 0.7071 = 25.4556

7 0
3 years ago
Simplify this expression:<br> -2x+3 -(5 - 64).<br> D
tatuchka [14]

Answer:

-2x+62

Step-by-step explanation:

-2x+3-(5-64)

-2x+3-5+64

-2x-2+64

-2x+62

7 0
3 years ago
How to solve for area of triangle where A=67 degrees, b=11yd, and c=24yd
skad [1K]

Use the formula of an area of a tringle:

A=\dfrac{1}{2}bc\sin A

We have b = 11 yd, c = 24 yd and m∠A = 67°

A=\dfrac{1}{2}(11)(24)\sin67^o

\sin67^o\approx0.9205\\\A=(11)(12)(0.9205)=121.506\ yd^2

4 0
3 years ago
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