Answer:
2x^2 = 6x - 5.
-x^2 - 10x = 34.
These have only complex roots/
Step-by-step explanation:
3x^2 - 5x = -8
3x^2 - 5x + 8 = 0
There are complex roots if the discriminant 9b^2 - 4ac) is negative.
Here the discriminant D = (-5)^2 - 4*-5*8 = 25 + 160
This is positive so the roots are real.
2x^2 = 6x - 5
2x^2 - 6x + 5 = 0
D = (-6)^2 - 4*2*5 = 36 - 40 = -4
So this has no real roots only complex ones.
12x = 9x^2 + 4
9x^2 - 12x + 4 = 0
D = (-12)^2 - 4*9 * 4 = 144 - 144 = 0.
- Real roots.
-x^2 - 10x = 34
x^2 + 10x + 34 = 0
D = (10)^2 - 4*1*34 = 100 - 136 = -36.
No real roots = only complex roots.
Answer:
Step-by-step explanation:
x < -12, so x+12 < 0
| x-(-12) | = | x+12 | = -x-12
Step-by-step explanation:
It seems here that they are asking us to solve for x
to do this we first need to factor
Since we can't factor this using the normal method we can instead do this
x^2 -4x-17=0
add 4 to both sides as it is a perfect square
x^2 - 4x + 4 = 17 +4
(x-2)^2 = sqrt 21
x-2 = ± 4.58
x -2 = 4.58 x-2 = -4.58
x= 6.58 x=-2.58
Or just say x=2+√21 or x=2−√21
Answer:
-10 is the correct answer to the given question .
Step-by-step explanation:
Missing information:
Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below
Triangle PQR has vertices 
It is translated according to the rule 
. What is the y-value of P'?
Now coming to the solution as already mention in the question
The translated rule is 
Now calculated the vertices P value according to the rule of translated
So -10 is the value of y in P vertices .
Answer:
x=4 hope that helps I did it on my calculator story if it is wrong
