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Lemur [1.5K]
3 years ago
10

Kis between J and M. Lis

Mathematics
2 answers:
otez555 [7]3 years ago
7 0
Step by step And the anwser is mn
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

MN

Step-by-step explanation:

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How can you find approximations of square roots?​
dem82 [27]

Step-by-step explanation:The second way of approximating a square root is to use a calculator. Most calculators have a radical sign on them. To find the square root of a number, we enter the radical sign, then the value and press enter. This will give us a decimal approximation of the square root.

5 0
2 years ago
Quadrilateral EFGH was dilated by a factor of 3. What is FG F'G'
Nikolay [14]
The coordinates would be multiplied by 3, as the scale factor is 3, and it is a dilation, so we know the size increases.
7 0
3 years ago
Read 2 more answers
What is the expansion of (3+x)^4
Vlad1618 [11]

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
6 0
3 years ago
Colin invests £2350 into a savings account. The bank gives 4.2% compound
marin [14]

Answer:

Answer:

£3692

Step-by-step explanation:

A = p(1 + r/n)^nt

Where,

A = future value

P = principal = £2350

r = interest rate = 4.2% = 0.042

n = number of periods = 1(annual)

t = time = 4 years

A = p(1 + r/n)^nt

= 2350(1 + 0.042/1)^1*4

= 2350(1 + 0.042)^4

= 2350(1.042)^4

= 2350(1.5789)

= 2770.42

A = £2770.42

Total years = 10

Remaining years = 10 – 4

= 6 years

Remaining 6 years

P = £2770.42

r = 4.9% = 0.049

n = 1

t = 6

A = p(1 + r/n)^nt

= 2770.42(1 + 0.049/1)^1*6

= 2770.42(1 + 0.049)^6

= 2770.42(1.049)^6

= 2770.42(1.3325)

= 3691.59

A = £3691.59

Approximately £3692

Thank you!

5 0
2 years ago
Si Adrián tiene “x” años de edad, Teresa la tercera parte de Adrián, Isabel el doble de Teresa y Felipe el cuádruple de Adrián,
bixtya [17]

the answer is ISABELLA YOUR BOYFRINDS HERE

4 0
2 years ago
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