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puteri [66]
2 years ago
5

The wingspans of a common species of housefly are normally distributed with a mean of 5mm and a standard deviation of 0.5mm. Sup

pose that a biologist regularly collects random samples of 20 of these houseflies and calculates the sample mean wingspan from each sample.
What will be the shape of the sampling distribution of the sample mean wingspan?
Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
6 0

Answer:

Approximately Normal

Step-by-step explanation:

Since the population is normally distributed, the sampling distribution of the sample mean will also be normally distributed, even when the sample size is small.

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The diameter is a line that stretches across the middle of a circle from end to end.  The radius is one half of this line, stretching from the center of the circle to a point on the side of the circle.  This means that the diameter is 2 times the length of the radius.  2 times 2 is 4, meaning that the diameter is 4 inches.
6 0
3 years ago
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I need help with this -15= n -8
4vir4ik [10]

Answer:

n = -7

Step-by-step explanation:

-15= n-8

n-8=-15

+8  +8

n=-7

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Which of the following represents the zeros of f(x) = 6x3 + 25x2 − 24x + 5?
cestrela7 [59]
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7 0
3 years ago
What is the distance between the longest dog in the shortest dog Short 7 over 8 longest 3 over 8 what is the difference
Step2247 [10]

Answer:

The distance between the longest dog and the shortest dog is 4 over 8 ( \frac{4}{8} ) OR 1 over 2 ( \frac{1}{2} )

Step-by-step explanation:

From the question,

Short is 7 over 8, that is,

Short = \frac{7}{8}

and longest is 3 over 8, that is

Longest = \frac{3}{8}

The distance between the longest dog and the shortest dog can be determined by finding the difference between the fractions. That is,

\frac{7}{8} - \frac{3}{8} = \frac{7 - 3}{8}

= \frac{4}{8}

= \frac{1}{2}

Hence, the distance between the longest dog and the shortest dog is 4 over 8 ( \frac{4}{8} ) OR 1 over 2 ( \frac{1}{2} ).

7 0
3 years ago
Trey Gorman invests $5,000 in a 1-year certificate of deposit that earns interest at an annual rate of 4% compounded monthly. Th
devlian [24]
The amount of interest for $5000 investment that earns 4% per year such that 1$ is $1.040742 a the end of the year will be as follows:
A=P(1+r/100)^n
P=principple
r=rate
n=time
Thus
Amount at the end of the year will be:
A=5000(1+4/100)^1=5200
thus interest earned will be:
5200-5000
=$200
3 0
3 years ago
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