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7nadin3 [17]
3 years ago
11

High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa

bility Challenge Exam. Students who score in the top 13 percent are recognized publicly for their achievement by the Department of the Treasury. Assuming a normal distribution, how many standard deviations above the mean does a student have to score to be publicly recognized

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
8 0

Answer:

A student have to score 1.28 standard deviations above the mean o be publicly recognized.

Step-by-step explanation:

If X \sim N (\mu, \sigma^{2}), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is, Z \sim N (0, 1).

The distribution of these <em>z</em>-variates is known as the standard normal distribution.

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean.

Thus, <em>z</em>-scores are a type of standardized scores.

It is provided that the students who score in the top 13 percent in the National Financial Capability Challenge Exam are recognized publicly for their achievement by the Department of the Treasury.

Let <em>x</em> be score of the top 13%.

So, to be are recognized publicly for their achievement by the Department of the Treasury the probability of score <em>x</em> must be:

P (X < x) = 0.90

⇒ P (Z < z) = 0.90

The value of <em>z</em> for the above probability is:

<em>z </em>= 1.28

*Use a <em>z</em>-table.

Thus, a student have to score 1.28 standard deviations above the mean o be publicly recognized.

daser333 [38]3 years ago
4 0

Answer:

The students have to score 1.13 standard deviations above the mean score to be publicly recognized.

Step-by-step explanation:

Mean = not given

Standard deviation = not given

Let Probability of Students who score in the top 13 percent = 13%

Probability of Students who score below the top 13 percent = Pr(<13%)

= 100% - 13% = 87%

Pr(<13%) = 0.87

To solve this, Use inverse of the standard normal cumulative distribution which has a mean of 0 and standard deviation of 1

Mean = 0

Standard deviation = 1

Probability used = 0.87

The z score associated with the highest 13 percent is found using excel formula:

=NORM.S.INV(0.87) = 1.1264

The students who score in the top 13 percent score is approximately 1.13 standard deviations above the mean score.

= mean + 1.13 Standard deviation

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Please help, fast‍♀️‍♀️
kramer

Inequalities are used to express unequal expressions.

The inequalities from the word problems are:

  • \mathbf{m - 3.5 \le -2}.
  • \mathbf{0 \ge 2x + 1}.
  • \mathbf{-\frac 12 \ge 2k - 4}

The statements from the inequalities are:

  • -4 is not a solution to \mathbf{x + 8 < -3}
  • -6 is not a solution to \mathbf{10 \le 3 - m}
  • -1 is not a solution to \mathbf{-3x \le -12.5}

  • Graph b represents \mathbf{x > -7}

<h3>The word problems</h3>

<u>1. A number minus 3.5 is less than or equal to -2</u>

The statement can be broken down into the following expressions

\mathbf{A\ number\ minus\ 3.5 \to m - 3.5}

\mathbf{less\ than\ or\ equal\ to\ -2 \to \le -2}

So, when the expressions are brought together, we have:

\mathbf{m - 3.5 \le -2}

<u>2. Zero is greater than or equal to twice a number x plus 1</u>

The statement can be broken down into the following expressions

\mathbf{Zero\ is\ greater\ than\ or\ equal\ to \to 0 \ge }

\mathbf{twice\ a\ number\ x\ plus\ 1\  \to 2x + 1}

So, when the expressions are brought together, we have:

\mathbf{0 \ge 2x + 1}

<u />

<u>3. -1/2 is at least twice a number k minus 4</u>

The statement can be broken down into the following expressions

\mathbf{-\frac 12\ is\ at\ least \to -\frac 12 \ge }

\mathbf{twice\ a\ number\ k\ minus\ 4\  \to 2k - 4}

So, when the expressions are brought together, we have:

\mathbf{-\frac12 \ge 2k - 4}

None of the options is correct

<h3>The solutions</h3>

<u>4. Tell whether -4 is a solution to x + 8 < -3</u>

We have:

\mathbf{x + 8

Subtract 8 from both sides

\mathbf{x + 8 - 8

\mathbf{x

The above inequality means that:

<em>x is less than -11</em>

-4 is not a solution, because -4 is greater than -11

<u>5. Tell whether -6 is a solution to 10 <= 3 - m</u>

We have:

\mathbf{10 \le 3 - m}

Subtract 3 from both sides

\mathbf{10 -3\le 3 - 3 - m}

\mathbf{7 \le  - m}

Multiply both sides by -1 (the inequality sign changes)

\mathbf{-7 \ge m}

Make m the subject

\mathbf{m \le -7}

The above inequality means that:

<em>m is less than -7</em>

-6 is not a solution, because -6 is greater than -7

<u>6. Tell whether -1 is a solution to -3x <= -12.5</u>

We have:

\mathbf{-3x \le -12.5}

Divide both sides by -3 (the inequality sign changes)

\mathbf{x \ge 4\frac16}

The above inequality means that:

<em>x is greater than or equal to </em>\mathbf{4\frac16}<em />

-1 is not a solution, because -1 is less than \mathbf{4\frac16}<em />

<h3>The graph</h3>

The inequality is given as: \mathbf{x > -7}

The less than sign (>) means that:

  • The graph would use an open circle
  • The arrow must point to the right

Only graph b satisfies this condition

Hence, the graph of \mathbf{x > -7} is graph b

Read more about inequalities at:

brainly.com/question/15137133

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