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snow_lady [41]
2 years ago
11

Write the equation of the line in point-slope form that goes through the points (0, 1) and (2, 7)

Mathematics
1 answer:
laiz [17]2 years ago
4 0

Answer:

point - slope form

 y - 1 = 3 (x-0)

Step-by-step explanation:

<u><em>step(i):-</em></u>

Given points are (0,1) and (2,7)

The slope of the line

     m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

    m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} } = \frac{7-1}{2-0} = \frac{6}{2}  = 3

  m =3

<u><em>Step(ii):-</em></u>

point -slope form

   y - y₁ = m(x-x₁)

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3

   y - 1 = 3 (x-0)

  y -1 = 3x

 3x - y +1=0

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3 is 3x -y +1=0

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The complete question is

"A theater production group is making frames to support wall-like props. Three-foot beams form right triangles with 10-foot beams to allow them to stand, as shown in the image.

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The value of angle x would be 16.7 degrees.

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2 years ago
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<img src="https://tex.z-dn.net/?f=8%20a%20b%20%5E%20%7B%202%20%7D%20%3A%206%20a%20%5E%20%7B%202%20%7D%20b" id="TexFormula1" titl
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\boxed{\large{\bold{\blue{ANSWER~:) }}}}

8ab^{2}:6a^{2}b\\\\=\dfrac{8ab^{2}}{6a^2b}\\\\=\dfrac{2×4×a×b×b}{2×3×a×a×b}\\\\=\dfrac{4b}{3a}\\\\=4b:3a

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