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madreJ [45]
3 years ago
7

Which equation could be used to find the height of the flagpole

Mathematics
1 answer:
Sauron [17]3 years ago
4 0
X = height of pole (in meters)

With respect to the 50 degree angle, the side x is the opposite leg. It is the leg furthest from the reference angle. The hypotenuse is 5 meters. 

The trig function sine ties together the opposite and hypotenuse

sin(angle) = opposite/hypotenuse
sin(50) = x/5
5*sin(50) = x .... multiply both sides by 5
x = 5*sin(50)

------------------

Since x = 5*sin(50) isn't listed as an answer choice, let's try using cosine. We can't use it right away because we don't know the adjacent side. What we can do is change the reference angle. The missing angle of the triangle is 90-50 = 40 degrees. Let's make the 40 degree angle the reference angle

So x is now the adjacent side with respect to the 40 degree reference angle. The hypotenuse is always the longest side. The hypotenuse stays at 5.

cos(angle) = adjacent/hypotenuse
cos(40) = x/5
5*cos(40) = x
x = 5*cos(40)

This expression is listed. The answer is choice B

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When you multiply any number by a fraction smaller than one, how does the original number change?
Eddi Din [679]

Answer:

It becomes smaller

Step-by-step explanation:

bc you r just taking a fraction(part) of the bigger number, so it becomes smaller.

8 0
4 years ago
Round 9118 to the nearest ten
gavmur [86]

(8)=ones place

(1)0=tens place

(1)00=hundreds place

(9)000=thousands place

The "1" beside the 8, is the tenths spot so you would round that part of the number.

Therefore the answer would be:

9120

6 0
3 years ago
The following table shows the times of trains between Juno and Odiham.
Luba_88 [7]

Answer:

(a) The earliest time that Ferdo can be back at Juno station is 12:15

Step-by-step explanation:

From the given table, we have;

The starting time for train departure from Juno = 07:15

The frequency of train departures from Juno = Every 20 minutes

The time of departure, 't₁' of first train that departs from Juno after 08:30 is given as follows;

The train departure times from Juno = 07:15, 07:35, 07:55, 08:15, 08:35

Therefore;

The time at which the first train departs from Juno after 08:30 = 08:35

The time it takes a train to travel from Juno to Odiham = 0:805 - 07:15 = 50 minutes

The time of arrival of the train Ferdo takes from Juno at Odiham = 08:35 + 50 minutes = 09:25

The number of hours Ferdo spends at Odiham = 2 hours

The time after which Ferdo departs from Odiham = 09:25 + 02:00 = 11:25

The time of departure of the train from Odiham after 11:25 = 08:05 + 20 minutes × 10

Therefore, the time of departure of the train from Odiham after = 11:25

The time it takes on the trip back to Juno from Odiham = 50 minutes

The earliest time that Ferdo can be back at Juno station = 11:25 + 50 minutes = 12:15

8 0
3 years ago
Factor. Check by multiplying<br> 2a - 14 = ?
SIZIF [17.4K]

Answer: 2a - 14 = 2(a - 7)

Step-by-step explanation:

Because 2•a = 2a and 2•-7= -4 therefore, the answer is 2(a - 7).

4 0
3 years ago
Read 2 more answers
What’s the answer (no link I give brainly)
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Answer:

the answer is A

Step-by-step explanation:

I had the same question and I got it correct

6 0
3 years ago
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