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belka [17]
3 years ago
15

Solve the system

%7D%7D%20%5Cright." id="TexFormula1" title="\left \{ {{y^2-26=-x^2} \atop {x-y=6}} \right." alt="\left \{ {{y^2-26=-x^2} \atop {x-y=6}} \right." align="absmiddle" class="latex-formula">

Mathematics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

Two solutions: (5, −1), (1, −5)

Step-by-step explanation:

Attached file has step-by-step procedure:

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A cabinet door is 13 inches wide and has an area of 260 inches. Use the formula A=lw. How tall is the cabinet door?
klio [65]

Answer:

20

Step-by-step explanation:

260/13=20

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8 0
3 years ago
May I please receive help?
romanna [79]

Answer:

\frac{10}{9}\pi      yards

Step-by-step explanation:

The circumference of this circle = 2πr

                                                     = 8π

We have to find the arc length of 50°, or 50/360 times the circumference of the circle(because there is 360° in a circle)

\frac{50}{360} * 8\pi = \\\\\frac{400\pi}{360} =\\\\ \frac{10\pi}{9}

-Chetan K

3 0
3 years ago
Group of kids rode horses to canyon. 20 eyes 30 legs between them. How many horses
Solnce55 [7]
If all were kids, there would be 20 legs. A horse has 2 more legs than a kid. The extra 10 legs can be attributed to there being 5 horses.
8 0
3 years ago
Solve by factoring<br> : 4x2=2x+3
evablogger [386]

Answer:

1+\sqrt{13}

________

    4

Step-by-step explanation:

6 0
3 years ago
Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0
3 years ago
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