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3 years ago

15

Solve the system

%7D%7D%20%5Cright." id="TexFormula1" title="\left \{ {{y^2-26=-x^2} \atop {x-y=6}} \right." alt="\left \{ {{y^2-26=-x^2} \atop {x-y=6}} \right." align="absmiddle" class="latex-formula">

1 answer:

const2013 [10]3 years ago

6 0

Answer:

Two solutions: (5, −1), (1, −5)

Step-by-step explanation:

Attached file has step-by-step procedure:

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(3x/2)^4 any answers

Anika [276]

$\bf \left( \cfrac{3x}{2} \right)^4\implies \left( \cfrac{(3x)^4}{2^4} \right)\implies \left( \cfrac{3^4x^4}{2^4} \right)\implies \cfrac{81x^4}{16}$

6 0

3 years ago

Read 2 more answers

2/9 divided by 4 what is the answer

Brrunno [24]

2/9 ÷ 4/1 (keep,change,flip) is 1/18.

3 0

3 years ago

Write 98 as the product of prime factors in ascending order

umka2103 [35]

to write 98 as a product of its prime factors we have to first find the prime factors of 98

prime factors are prime numbers by which the given number can be divided by.

98 we have to keep dividing it by prime numbers

98 is an even number so we can first divide by 2

98 / 2 = 49

49 is a multiple of 7 which too is a prime number so we can divide 49 by 7

49/7 = 7

7 can be divided again by 1

7/7 = 1

98 is divisible by 2 and 7

so 98 written as a product of prime factors is

98 = 2 x 7 x 7

4 0

2 years ago

Read 2 more answers

In a random sample of 8 people, the mean commute time to work was 33.5 minutes and the standard deviation was 7.2 minutes. A 95

Elina [12.6K]

Answer: Margin of error = 6.58

Confidence interval = (26.91, 40.08)

Step-by-step explanation:

Since we have given that

Sample size n = 8

Sample mean = 33.5 minutes

Population standard deviation = 9.5 minutes

At 95% confidence interval,

α = 0.05

t = 1.96

So, Margin of error is given by

$t\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{9.5}{\sqrt{8}}\\\\=6.58$

Confidence interval would be

Lower limit:

$\bar{x}-6.58\\\\=33.5-6.58\\\\=26.91$

Upper limit:

$\bar{x}+6.58\\\\=33.5+6.58\\\\=40.08$

Hence, the interval would be (26.91, 40.08)

But at standard deviation 7.2 minutes, the confidence interval was (27.5, 39.5)

Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.

3 0

3 years ago

Sylvia surveyed her classmates at school to find out who plays sports at her school.the table below shows the number of students

Neporo4naja [7]

Answer:

Using the info you just gave,

Basketball, 8 studentsfootball, 7 studentsSoccer 12 studentsother, 13 students

We can now figure out the percentage of students that did NOT select soccer.

First, you need to add all the students together.

8 + 7 + 12 + 13

You get 40 students all together.

Now, add together the students that DID NOT choose soccer.

7 + 8 + 13 = 29

That means that 28/40 of the students did not choose soccer.

Now, convert that to a percentage.

28/40 = 0.7

To make that into a percentage, multiply by 100

Thus, the percentage of students that did not select soccer is 70%.

Hope this helped!

7 0

2 years ago